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schepotkina [342]
3 years ago
14

Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .

Physics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

4.0932672025\times 10^{-17}

Explanation:

E_a = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

f=e^{-\dfrac{E_a}{RT}}\\\Rightarrow f=e^{-\dfrac{160000}{8.314\times 510}}\\\Rightarrow f=4.0932672025\times 10^{-17}

The fraction of energy is 4.0932672025\times 10^{-17}

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What is an indicator species? Give an example.
Butoxors [25]

Answer:

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Which of the following is NOT a part of the respiratory system?
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3 years ago
A proton initially at rest is accelerated by a uniform electric field. The proton moves 4.76 cm in 1.10 x 10^-6 s. Find the volt
iVinArrow [24]

Answer:

The voltage drop through which the proton moves is 39.1 V.

Explanation:

Given that,

Distance = 4.76 cm

Time t=1.10\times10^{-6}\ s

We need to calculate the acceleration

Using equation of motion

s = ut+\dfrac{1}{2}at^2

Where, s = distance

a = acceleration

t = time

Put the value in the equation

4.76\times10^{-2}=\dfrac{1}{2}\times a \times(1.10\times10^{-6})^2

a=\dfrac{2\times 4.76\times10^{-2}}{(1.10\times10^{-6})^2}

a=7.87\times10^{10}\ m/s^2

We need to calculate the voltage drop

Using formula of electric field

F=qE

F = q\dfrac{V}{d}....(I)

Using newton's second law

F = ma....(II)

Put the value of F in equation (I) from equation (II)

ma=\dfrac{qV}{d}

V=\dfrac{mad}{q}

Where, q = charge

a = acceleration

d = distance

m= mass of proton

Put the value into the formula

V=\dfrac{1.67\times10^{-27}\times7.87\times10^{10}\times4.76\times10^{-2}}{1.6\times10^{-19}}

V=39.1\ V

Hence, The voltage drop through which the proton moves is 39.1 V.

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