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bixtya [17]
3 years ago
9

A horizontal force FFaa���⃗ of magnitude 20.0 N is applied to a 3.00 kg psychology book as the book slides a distance d = 0.500

m up a frictionless ramp at angle θ = 30.0°. (a) During the displacement, what is the net work done on the book? (b) If the book has zero kinetic energy at the start of the displacement, what is its speed at the end of the displacement?
Physics
1 answer:
alina1380 [7]3 years ago
7 0

Answer:

(a) W = 8.66 J

(b) Velocity = 2.40 m/s

Explanation:

(a) Work done is given as the product of force and displacement. That is:

W = F * d * cos(A)

Where F = force applied

d = distance moved

A = angle of ramp

Therefore, work done is:

W = 20 * 0.5 * cos30

W = 8.66 J

(b) Work done is equal to change in Kinetic energy. Since the initial kinetic energy is zero:

W = KE(final)

W = ½ * m * v²

Where v = final velocity

=> 8.66 = ½ * 3 * v²

v² = 5.773

v² = 2.40 m/s

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Answer:

The answer is 100J.

Explanation:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. In this question, the mass is equals to 50kg and the velocity is 2m/s

Now,

25kg×4m/s^2 = 100kgm/s^2 or 100J

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3 years ago
A 103 kg horizontal platform is a uniform disk of radius 1.71 m and can rotate about the vertical axis through its center. A 68.
Andreyy89

Answer:

I_{total}=220.64 kg*m^{2}

Explanation:

The moment of inertia of the system is equal to the each population and the platform inertia so

Inertia disk

I_{disk}=\frac{1}{2}*m_{disk}*(r_{p})^{2}

Inertia person

I_{p}=\frac{1}{2}*m_{p}*(r_{p})^{2}

Inertia dog

I_{d}=\frac{1}{2}*m_{d}*(r_{d})^{2}

The Inertia of the system is the sum of each mass taking into account that all exert the force of inertia:

I_{total}=I_{disk}+I_{p}+I_{d}

I_{total}=\frac{1}{2}*103kg*(1.71)^{2}+\frac{1}{2}*68.9kg*(1.09)^{2}+\frac{1}{2}*27.7kg*(1.45)^{2}

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A density triangle is a tool that can be used to find
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The answer is D
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4 0
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If Mrs. Reichelt throws a chromebook, because it won't login correctly, with a force of 8N, and the chromebook accelerates at 5m
suter [353]

Answer:

1.6 kg

Step-by-step Solution:

Since Force = mass × acceleration we have:

F = 8N

a= 5 m/s^2

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By plugging the values above into F=ma we obtain:

F=ma\\\\8=m(5)\\\\\frac{8}{5}=\frac{m(5)}{5}\\\\m=\frac{8}{5}=1.6

Therefore, the Chromebook has a mass of 1.6 kilograms.



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4 years ago
Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of
Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

s = at^2/2 = 5t^2/2 = 2.5t^2

We can take derivative of this with respect to time t to get the equation of slope:

s' = (2.5t^2)' = 2*2.5t = 5t

As time t increase, the slope would increases with time as well.

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