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Cloud [144]
3 years ago
12

Through which one of the following mediums is the velocity of a sound wave the greatest?

Physics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer: <u><em>C. Steel</em></u>

Explanation: <em><u>When a sound wave travels through a solid body consisting</u></em>

<em><u /></em>

<em><u>of an elastic material, the velocity of the wave is relatively</u></em>

<em><u /></em>

<em><u>high. For instance, the velocity of a sound wave traveling</u></em>

<em><u /></em>

<em><u>through steel (which is almost perfectly elastic) is about</u></em>

<em><u /></em>

<em><u>5,060 meters per second. On the other hand, the velocity</u></em>

<em><u /></em>

<em><u>of a sound wave traveling through an inelastic solid is</u></em>

<em><u /></em>

<em><u>relatively low. So, for example, the velocity of a sound wave</u></em>

<em><u /></em>

<em><u>traveling through lead (which is inelastic) is approximately</u></em>

<em><u /></em>

<em><u>1,402 meters per second.</u></em>

<em><u /></em>

<u><em /></u>

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NEED HELP ASAP! DUE NOW!!
docker41 [41]
Oh okay the first person who answered is incorrect but


0—> PE=0J

1—>PE=1J

20—>PE=20J

50—>PE=50J

100—>PE=100J
4 0
3 years ago
The amount of force needed to sustain motion of a rock in outer space is
BartSMP [9]

Answer:

0 N

Explanation:

According to Newton's first law, object subjected to no force or 0 net force will stay in the same motion. In outer space, there's no gravity or air resistance. So if the net force is 0, a rock in motion would be still in motion forever without a need of an extra force to sustain it.

4 0
3 years ago
A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete
arlik [135]

Answer:

0.0389 cm

Explanation:

The current density in a conductive wire is given by

J=\frac{I}{A}

where

I is the current

A is the cross-sectional area of the wire

In this problem, we know that:

- The fuse melts when the current density reaches a value of

J=520 A/cm^2

- The maximum limit of the current in the wire must be

I = 0.62 A

Therefore, we can find the cross-sectional area that the wire should have:

A=\frac{I}{J}=\frac{0.62}{520}=1.19\cdot 10^{-3} cm^2

We know that the cross-sectional area can be written as

A=\pi \frac{d^2}{4}

where d is the diameter of the wire.

Re-arranging the equation, we  find the diameter of the wire:

d=\sqrt{\frac{4A}{\pi}}=\sqrt{\frac{4(1.19\cdot 10^{-3})}{\pi}}=0.0389 cm

3 0
3 years ago
If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength?
madam [21]
B. Wrap more coils of wire around the nail
Increasing the number of coils in an electromagnet increases the strength of the magnetic field.
4 0
3 years ago
Read 2 more answers
3. What is the acceleration of a 10 kg mass pushed by a 5 N force?
insens350 [35]

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

Explanation:

Brainliest?

5 0
3 years ago
Read 2 more answers
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