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Cloud [144]
3 years ago
12

Through which one of the following mediums is the velocity of a sound wave the greatest?

Physics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer: <u><em>C. Steel</em></u>

Explanation: <em><u>When a sound wave travels through a solid body consisting</u></em>

<em><u /></em>

<em><u>of an elastic material, the velocity of the wave is relatively</u></em>

<em><u /></em>

<em><u>high. For instance, the velocity of a sound wave traveling</u></em>

<em><u /></em>

<em><u>through steel (which is almost perfectly elastic) is about</u></em>

<em><u /></em>

<em><u>5,060 meters per second. On the other hand, the velocity</u></em>

<em><u /></em>

<em><u>of a sound wave traveling through an inelastic solid is</u></em>

<em><u /></em>

<em><u>relatively low. So, for example, the velocity of a sound wave</u></em>

<em><u /></em>

<em><u>traveling through lead (which is inelastic) is approximately</u></em>

<em><u /></em>

<em><u>1,402 meters per second.</u></em>

<em><u /></em>

<u><em /></u>

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A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve
amm1812

<u>Answer</u>:

The velocity of the tennis racket after the collision 14.966 m/s.

<u>Step-by-step explanation:</u>

let the following:

m₁ = mass of tennis racket = 0.311 kg

m₂ = mass of the ball = 0.057 kg

u₁ = velocity of tennis racket before collision = 30.3 m/s

u₂ = velocity of the ball before collision = -19.2 m/s

v₁ = velocity of tennis racket after collision

v₂ = velocity of the ball after collision

Right (+) , Left (-)

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

So, the total kinetic energy before collision = the total kinetic energy after collision.

So, 0.5 m₁ u₁² + 0.5 m₂ u₂² = 0.5 m₁ v₁² + 0.5 m₂ v₂²  ⇒ (1)

Also, the total momentum before collision = the total momentum after collision.

So, m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂  ⇒ (2)

Solving (1) and (2):

∴ v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

      = ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)

      = 14.966 m/s.

So, the velocity of the tennis racket after the collision 14.966 m/s.

7 0
3 years ago
Atoms in a molecule are bonded together by sharing gaining or losing_
Alex

It is by gaining! I just learned this in school. Hope this helps:)

3 0
2 years ago
Read 2 more answers
. What is the relationship between potential energy, kinetic energy, and speed as the skater moves down and up the U-shaped ramp
kykrilka [37]
Top of the U ramp: potential energy is the highest, while kinetic energy is the lowest

Bottom of the U ramp(aka the curve part): potential energy is the lowest and the kinetic energy is the highest

THEREFORE, PE and KE have an INVERSE RELATIONSHIP.
6 0
3 years ago
Read 2 more answers
[High Dive) above a pool of water. According to the announcer, the divers enter the water at a speed of 56 mi/h (25 m/s). (Air r
blsea [12.9K]

Answer:

(a) The announcer's claim is incorrect because the divers enter at a speed of 20.4 and not 25 m/s as announced

(b)  it’s possible for a diver to enter the water with the velocity of 25 m/s if he has initial velocity of 14.4 m/s. The upward initial velocity can’t be physically attained

Explanation:

(a)

To find the final velocity V_{f} for an object traveling distance h taking the initial vertical component of velocity as V_{i} the kinematics equation is written as

V_{f}^{2}=V_{i}^{2}+2ah where a is acceleration

Substituting g for a where g is gravitational force value taken as 9.81

V_{f}^{2}=V_{i}^{2}+2gh

Since the initial velocity is zero, we can solve for final velocity by substituting figures, note that 70 ft is 21.3 m for h

V_{f}=\sqrt {(2gh)}= V_{f}=\sqrt {(2*9.81*21.3)}= 20.44275

Therefore, the divers enter with a speed of 20.4 m/s

The announcer's claim is incorrect because the divers enter at a speed of 20.4 and not 25 m/s as announced

(b)

The divers can enter water with a velocity of 25 m/s only if they have some initial velocity. Using the kinematic equation

V_{f}^{2}=V_{i}^{2}+2gh

Since we have final velocity of 25 m/s

V_{i}^{2}=2gh-V_{f}^{2}

V_{i}=\sqrt{(V_{f}^{2}-2gh)}

V_{i}=\sqrt{(25^{2}-2*9.81*21.3)}= 14.390761 m/s

Therefore, it’s possible for a diver to enter the water with the velocity of 25 m/5 if he has initial velocity of 14.4 m/s

In conclusion, the upward initial velocity can’t be physically attained

3 0
3 years ago
I need help on these 3 questions plz 20 points
Dmitry_Shevchenko [17]

Answer: the first one is speed

the second one is acceleration

the last is velocity

Explanation:

i got you

4 0
3 years ago
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