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3 years ago

Help me PLZZZZ ITSS EASSYYYYYY

Mathematics

1 answer:

vodka [1.7K]3 years ago

5 0

Answer:

The total cost y of a meal.....

Step-by-step explanation:

The total cost of the meal Y suggests addition, which if you added the x and w portions, you would end up with y.

The other answers suggest subtraction, division, or multiplication, which is not being illustrated by the model.

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6 numbers are shown

Sonja [21]

Answer:

$-1\frac{1}{2}$ , $-\frac{3}{4}$ , $-\frac{37}{50}$ , $\frac{5}{4}$ , $1\frac{1}{4}$ , $2\frac{3}{4}$

Step-by-step explanation:

$1\frac{1}{4}$ , $-1\frac{1}{2}$ , $-\frac{37}{50}$ , $-\frac{3}{4}$ , $2\frac{3}{4}$ , $\frac{5}{4}$

Order everything, negative to the left side and positive to the right side

Negative numbers:

$-1\frac{1}{2}$ , $-\frac{37}{50}$ , $-\frac{3}{4}$

Positive numbers:

$1\frac{1}{4}$ , $2\frac{3}{4}$ , $\frac{5}{4}$

Now order it on a number line:

$-1\frac{1}{2}$ , $-\frac{3}{4}$ , $-\frac{37}{50}$ , $\frac{5}{4}$ , $1\frac{1}{4}$ , $2\frac{3}{4}$

8 0

3 years ago

The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of

Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

$X \sim N(3.34,0.07^2)$

Value let separated the top 3% is T and for bottom it would be B

$P(X < T)= 0.97$

Now converting, we get

$P(Z < \frac{T-3.34}{0.07})= 0.97$

Based on the normal standard tables, we get

$P(Z < 1.881)= 0.97$

Now compare these two above equations

$\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47$

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

$P(Z < \frac{B-3.34}{0.07})= 0.03$

Based on the normal standard tables, we get

$P(Z < -1.881)= 0.03$

Now compare these two above equations

$\frac{B-3.34}{0.07} = -1.881$

$= -1.881 \times 0.07 + 3.34 \\\\ = 3.21$

hence, for bottom it would be 3.21

7 0

2 years ago

to analyze the test scores of students in a math class, would a teacher use a dot plot or histogram to represent the scores? bri

frutty [35]

A bar graph would be a better choice because it is able to show how often he/she has gotten a good score.

5 0

3 years ago

Read 2 more answers

Step 1: Subtract 3 from both sides of the inequality

Tpy6a [65]

Answer:

add 8x to both sides

Step-by-step explanation:

5-8x<2x+3

first step, subtract 3 from both sides:

2-8x<2x

second step,?

2<?x

so you need to add 8x first

3 0

3 years ago

) a, p and d are n×n matrices. check the true statements below:

BigorU [14]

A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose $\mathbf P$ is the matrix of the eigenvectors of $\mathbf A$ , and $\mathbf D$ is the diagonal matrix of the eigenvalues of $\mathbf A$ :

$\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}$

$\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}$

Then

$\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}$

In other words, the columns of $\mathbf{AP}$ are $\mathbf{Av}_i$ , which are identically $\lambda_i\mathbf v_i$ , and these are the columns of $\mathbf{PD}$ .

c. False. A counterexample is the matrix

$\begin{bmatrix}1&1\\0&1\end{bmatrix}$

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

$\begin{bmatrix}0&1\\0&0\end{bmatrix}$

with eigenvalue $\lambda=0$ and eigenvector $\begin{bmatrix}k&0\end{bmatrix}^\top$ , where $k\in\mathbb R$ . But the matrix can't be diagonalized.

7 0

3 years ago