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aksik [14]
2 years ago
6

I was wondering if anyone could help me on this question, I'm really stuck on it!

Mathematics
1 answer:
borishaifa [10]2 years ago
5 0
It would be the first one because you are multiplying P by -7 to get the value q
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Find the value of this expression if x = -9.<br> x2 + 3<br> x +6
iren [92.7K]

Answer:

Step-by-step explanation:

x² + 3 = (-9)² + 3          {  (-9)² = -9 *-9 = 81}

     = 81 + 3

       = 84

x + 6 = -9 + 6 = -3

7 0
3 years ago
Please help if you answer correctly I will give brainliest thank you!!!!!!!!
ivolga24 [154]

Answer:

The Answer is C

Step-by-step explanation:

3x-4y=5

2x+4y=-3

This equation is the answer to this problem because just by looking at it, you can immediately cancel out the y value and solve for x.

The other equations are wrong because their is extra work needed to eliminate the values.

4 0
2 years ago
Which number completes the square? x2 − 20x + _____?
OverLord2011 [107]
100, because, x^2 - 20x + 100 = ( x - 10 )^2;
4 0
3 years ago
The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

7 0
3 years ago
Q. What do "zeros" represent?<br> HELPP
Bas_tet [7]

Answer:

The one your mouse is on

Step-by-step explanation:

4 0
2 years ago
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