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3 years ago

A pyramid has a square base with an area of 169ft. What is the perimeter of the base of the pyramid?

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer:52 ft.

Step-by-step explanation: If the area of the base of the pyramid is

169

then each side of the base is

long because the base of the pyramid is a square.

Length of the side,

√

169

Iif we take the area of a square

where

we get the area of the base to be

169

thus proving that each side of the base is

long.

So to find the perimeter of the base of the pyramid we use the formula:

where

and thus,

⋅

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What is the area of the piece of red paper after the hole for

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Answer:

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Explanation:

The complete question is:

A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.

On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).

What is the area of the piece of red paper after the hole for the photograph has been cut?

<h2>Solution</h2>

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

1. Area of the big rectangle

Vertices:

(- 4, 4)
(4, 4)
(4, -4)
(-4, -4)

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

$4-(-4)=4+4=8$

The area of this square is $(8unit)^2=64unit^2$

2. Area of the small square

Vertices:

(-3, -2)
(- 2, 2)
(2, 1)
(1, -3)

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}$

The area is:

$(\sqrt{17}unit)^2}=17unit^2$

3. Area of the piece of red paper after the holw for the photograph has been cut:

Find the difference:

$64unit^2-17unit^2=47unit^2$

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Answer:

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