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nata0808 [166]
2 years ago
6

G(x)=2x-1 h(x)=x^2-3x find g(x)+h(x)

Mathematics
2 answers:
Nikolay [14]2 years ago
7 0
I think its g(x^2-3x)=2x^2-6x-1
avanturin [10]2 years ago
5 0

Answer:

(2x - 1) +  ({x}^{2}  - 3x) \\  =    {x}^{2}   - 1x - 1 \\

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Well if its exponential it must be x ^n

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Someone help me with this question pleaseee
sweet-ann [11.9K]
Answer: y=2x-1

We know that the equation of a line is y = mx + b, where m is the gradient and b is the y-intercept.

First to find the gradient, we use the formula y2-y1/x2-x1.

x1 and y1 being the first set of coordinates (2,3) and x2 and y2 being the second set (4,7)

Now we sub in:
m=7-3/4-2
m=4/2
m=2

This is our gradient and we can put it into the equation: y=2x+b

Now we find the y-intercept (b). Since the y-intercept isn’t shown, we can sub in the coordinates to find it.

y=2x+b
Sub (2,3)
3=2(2)+b
3=4+b
-1=b

Sub (4,7)
7=2(4)+b
7=8+b
-1=b

Subbing in both coordinates gives us -1 as the y-intercept, so the finished equation is: y=2x-1
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Evgesh-ka [11]
There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.

Even means the graph is symmetric about the y-axis

The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)

because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).

Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
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