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frosja888 [35]
3 years ago
5

What is a repeat remainder

Mathematics
2 answers:
ad-work [718]3 years ago
6 0
Where the number is like this .030303030303...
Fiesta28 [93]3 years ago
5 0
It’s pretty much where part of the number is repeated. For example, 0.0087878787 (87 is repeated) or 0.0567567567 (567 is repeated)
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Consider the equation
earnstyle [38]

a) true

b) false

c) true

Step-by-step explanation:

<h3>let's determine the first statement</h3><h3>to determine x-intercept </h3><h3>substitute y=0</h3>

so,

8x-2y=24

8x-2.0=24

8x=24

x=3

therefore

the first statement is <u>true</u>

let's determine the second statement

<h3>to determine y-intercept </h3><h3>substitute x=0</h3>

so,

8x-2y=24

8.0-2y=24

-2y=24

y=-12

therefore

the second statement is <u>False</u>

to determine the third statements

<h3>we need to turn the given equation into this form</h3><h2>y=mx+b</h2><h3>let's solve:</h3>

8x-2y=24

-2y=-8x+24

y=4x-12

therefore,

the third statement is also <u>true</u>

4 0
2 years ago
Right answer gets brainlist
Vladimir [108]

105 i think nvm not corrupted picture

4 0
3 years ago
mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma
Aneli [31]
First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: r= \frac{c^2}{8m} + \frac{m}{2}
where 
c is the length of the chord 
m is the middle ordinate 
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so c=52 and m=6. Lets replace those values in our formula:
r= \frac{52^2}{8(6)} + \frac{6}{2}
r= \frac{2704}{48} +3
r= \frac{169}{3} +3
r= \frac{178}{3}

Next, to find the minimum speed, we are going to use the formula: s= \sqrt{15fr}
where
f is <span>drag factor
</span>r is the radius 
We know form our problem that the drag factor is 0.2, so f=0.2. We also know from our previous calculation that the radius is \frac{178}{3}, so r= \frac{178}{3}. Lets replace those values in our formula:
s= \sqrt{(15)(0.2)( \frac{178}{3}) }
s= \sqrt{178}
s=13.34 mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour. 
8 0
3 years ago
This question has two parts. First, answer Part A. Then, answer Part B.
ss7ja [257]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
Point A is located at (-3, 9) and point B is located at (12,-10). Find the distance from point A to point B rounded to the neare
Nezavi [6.7K]

Answer:

20

Step-by-step explanation:

\sqrt{(( - 10) - 9)^{2}  + (12 - ( - 3)) ^{2} }

\sqrt{( - 19)^{2}  + (15)^{2} }

\sqrt{361 + 225}

\sqrt{586}

24.2074

7 0
2 years ago
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