Answer:
x = - 4, 0, 3, 4
Step-by-step explanation:
Given
f(x) = - 5x(x² - 16)(x - 3) ← x² - 16 is a difference of squares, thus
f(x) = - 5x(x - 4)(x + 4)(x - 3)
To find the zeros, equate f(x) to zero, that is
- 5x(x - 4)(x + 4)(x - 3) = 0
Equate each factor to zero and solve for x
- 5x = 0 ⇒ x = 0
x - 4 = 0 ⇒ x = 4
x + 4 = 0 ⇒ x = - 4
x - 3 = 0 ⇒ x = 3
Thus the zeros are
x = - 4, x = 0, x = 3, x = 4
I’m sure the answer is B.
You loser
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Y = ax + b;
0.89 = a * 2 + b and 2.09 = a * 5 + b =>
=> 2.09 - 0.89 = a * 5 + a * 2 + b - b => 1.20 = 3 * a => a = 1.20 / 3 => a = 0.40;
b = 0.89 - 0.40 * 2 => b = 0.89 - 0.80 => b = 0.09;
y = 0.40x + 0.09 => 0.40x - y + 0.09 = 0 is the linear equation.
