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schepotkina [342]
3 years ago
15

Guys please, please help!!

Mathematics
2 answers:
vesna_86 [32]3 years ago
8 0

9514 1404 393

Answer:

  1. domain and range are all real numbers

  2. the relation is linear

Step-by-step explanation:

When the graph of a function is a straight line, the relation is linear. (That's what linear means.)

A linear relation is of degree 1, so has odd degree. Any odd-degree polynomial function has a domain and range of "all real numbers."

Lelechka [254]3 years ago
4 0

Answer:

1. Domain : all the real numbers

Range = all the real numbers

yes, this relation represents a linear function. (linear functions are always a straight line when graphed.)

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Graph the linear equation x= - 5​
Grace [21]

Answer:

that would be a vertical line (parallel to the y axis) that passes through -5 on the X axis

Step-by-step explanation:

just a straight line that goes through x = -5. if you're still confused it would also go through the point (-5, -5) a straight vertical line

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Two supplementary angles differ by 34. find the angles..​
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Answer:

107°

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Step-by-step explanation:

Let the two supplementary angles be x° and y°.

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Since, supplementary angles differ by 34.

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Adding equations (1) & (2)

x + y = 180

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Solve the system of equations by graphing: -1/3x + y=-1, y=4+1/3x
Arada [10]

-\frac{1}{3}x + y = -1   ⇒   y = \frac{1}{3}x - 1

To graph this line, plot a point at the y-intercept (0, -1), than plot the next point using the rise over run from the slope (\frac{1}{3}) by counting up 1 and to the right 3 of the y-intercept.  This gives you a second point of (3. 0).  Draw a line through those two coordinates.

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***************************************************************************************

y = 4 +  \frac{1}{3}x    ⇒   y =  \frac{1}{3}x  + 4

Same as above.  Plot the y-intercept (0, 4) and then use rise over run from the slope to plot (3, 5).

Answer: Plot (0, 4) and (3, 5) and draw a line through them.

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4 years ago
A+b+c=31 2a+3b+4c=105 who's a,b,c
Alik [6]

Answer:

begin{aligned}

   & x = \frac{D_x}{D} = \frac{-616}{-154} =  4 \\

   & y = \frac{D_y}{D} = \frac{ 616}{-154} = -4 \\

   & z = \frac{D_z}{D} = \frac{-770}{-154} =  5

         \end{aligned}begin{aligned}    & x = \frac{D_x}{D} = \frac{-616}{-154} =  4 \\    & y = \frac{D_y}{D} = \frac{ 616}{-154} = -4 \\    & z = \frac{D_z}{D} = \frac{-770}{-154} =  5          \end{aligned}

Step-by-step explanation:

4 0
4 years ago
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