Answer:
a) 29.23% probability that a randomly selected home run was hit to right field
b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.
(a) What is the probability that a randomly selected home run was hit to right field?
Desired outcomes:
19 home runs hit to right field
Total outcomes:
65 home runs
19/65 = 0.2923
29.23% probability that a randomly selected home run was hit to right field
(b) Was it unusual for this player to hit a home run to right field?
29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Answer : The fifth term in the sequence is -2.
Step-by-step explanation :
As we are given that the expression to calculate the 
term.
The expression is as follows:
where,
n is the number of term
Given:
n = 5
Now putting the value of n in the above expression, we get:
Therefore, the fifth term in the sequence is -2.
Answer:
32.2 is your answer for c
Step-by-step explanation:
Note the equation:
c - 23.7 = 8.5
Note the equal sign. What you do to one side, you do to the other. Isolate the c. add 23.7 to both sides
c - 23.7 (+23.7) = 8.5 (+23.7)
c = 8.5 + 23.7
Simplify.
c = 32.2
32.2 is your answer for c
~
We know that
38% of the incoming students own both a smartphone and a tablet
84% of the students own a smartphone
We are asked to find the percentage of students who own a smartphone
Let N be the total number of incoming students and S be the total number of students
So,
(N (38%) + S (84%)) / (N + S)
If we know the total number of students or incoming students, we can solve for the percentage by substituting the value of N or S
