<u><em>Answer:</em></u>
y = -x² + 60x + 256 in²
<u><em>Explanation:</em></u>
<u>Before we begin, remember the following:</u>
yᵃ × yᵇ = yᵃ⁺ᵇ
<u>Now, for the given problem:</u>
We know that the area of the rectangle is the product of its dimensions (length and width)
<u>This means that:</u>
Area of rectangle = length × width
<u>Now, we are given that:</u>
length of game board = x+4 in
width of game board = -x+64 in
<u>Substitute with the givens in the rule it as follows: </u>
Area of rectangle = length × width
Area of board game = (x+4)(-x+64)
<u>Use the distributive property, compute the product and gather like terms as follows:</u>
Area of board game = (x+4)(-x+64)
Area of board game = x(-x) + x(64) +4(-x) +4(64)
Area of board game = -x² + 64x - 4x + 256
Area of board game = -x² + 60x + 256 in²
Hope this helps :)
Idk u think I you use division I just really want point ♀️
2x-14=x-2 subtract x from both sides
x-14=-2 add 14 to both sides
x=12
hope this helps
Answer:
a) 28,662 cm² max error
0,0111 relative error
b) 102,692 cm³ max error
0,004 relative error
Step-by-step explanation:
Length of cicumference is: 90 cm
L = 2*π*r
Applying differentiation on both sides f the equation
dL = 2*π* dr ⇒ dr = 0,5 / 2*π
dr = 1/4π
The equation for the volume of the sphere is
V(s) = 4/3*π*r³ and for the surface area is
S(s) = 4*π*r²
Differentiating
a) dS(s) = 4*2*π*r* dr ⇒ where 2*π*r = L = 90
Then
dS(s) = 4*90 (1/4*π)
dS(s) = 28.662 cm² ( Maximum error since dr = (1/4π) is maximum error
For relative error
DS´(s) = (90/π) / 4*π*r²
DS´(s) = 90 / 4*π*(L/2*π)² ⇒ DS(s) = 2 /180
DS´(s) = 0,0111 cm²
b) V(s) = 4/3*π*r³
Differentiating we get:
DV(s) = 4*π*r² dr
Maximum error
DV(s) = 4*π*r² ( 1/ 4*π*) ⇒ DV(s) = (90)² / 8*π²
DV(s) = 102,692 cm³ max error
Relative error
DV´(v) = (90)² / 8*π²/ 4/3*π*r³
DV´(v) = 1/240
DV´(v) = 0,004
Grade 7 : Yes = 2 , No = 3
Grade 8 : Yes = 1 , No = 4
