All categories

3 years ago

Round 907.457 to the nearest tents place

Mathematics

2 answers:

eduard3 years ago

8 0

the awnseer is 910 jfakfneanfeg

Wewaii [24]3 years ago

7 0

Answer:

The answer is 907.5.

Step-by-step explanation:

The tenths place is the number just after the decimal. To round, we need to look at the number just to the right of the digit we need to round to. In this case, that number is 5. Now, if the digit to the right is anywhere from 1-4, we round down, by which I mean we keep the number the same. But if it is from 5-9, we round up. Therefore, we round up in this case, getting 907.5.

You might be interested in

Ok so i have to write something

kap26 [50]

(11/3-7/4)/[3.4-(1/2+2/3*3/2)]

First I converted fractions to mixed numbers.

11/3-7/4 / 3.4-3/2

Then, I solve the inside of the parentheses.

23/12 / 3.4-3/2

Continue to simplify

Convert to decimals

1.91667/1.9

Hope this helps

6 0

2 years ago

2. There were 35 children and 10 adults at a cookout.

qwelly [4]

Answer:

a.2:7

b.7:9

c.4:5

hope it helps

Explanation -

a. as original ratio is 10/35 , we reduce it to 2:7.

b. as original ratio is 35/45 , we reduce it to 7:9

c. as original ratio is 40:50 , we reduce it to 4:5

5 0

2 years ago

A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What

kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

Solution:

Let width = $x\ cm$

Length = $x+3\ cm$

Height = $x+3+4=x+7\ cm$

As we know:

$Volume\ of\ box=length\times width\times height$

$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$