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nata0808 [166]
3 years ago
8

Show questions

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

The cost is a fixed $2, plus $3.25 for any additional hour.

Then if you rent it for x hours, the cost is:

c(x) = $2 + $3.25*x

Is this situation continuous or discrete?

Yes, it is discrete, because x is "the number of hours"

so if you rent it for 1.30 hours, they will say "ok, this is equivalent to two hours".

This means that while the values of x are continuous, the possible costs are:

{$2, $2 + $3.25, $2 + 2*$3.25, ....}

Which is a discrete set.

Then the sign for 1 to 5 hours will be:

1 hour ---------- $2 + $3.25 = $5.25

2 hours -------- $2 + 2*$3.25 = $8.50

3 hours--------- $2 + 3*$3.25 = $11.75

4 hours--------- $2 + 4*$3.25 =  $15

5 hours -------- $2 + 5*$3.25 = $18.25

In the other park the cost is only $4 for each hour (no fixed cost) then the total cost for x hours is:

c(x) = $4*x

Now, which option is better?

If we look at the costs for different numbers of hours for this other equation, we have:

1 hour ----- $4

2 hours ---- 2*$4 = $8

3 hours ----- 3*$4 = $12

4 hours ------ 4*$4 = $16

Then: if you want to skate 2 hours or less, Skate City is cheaper, if you want to skate more than that, kate Days is cheaper.

This happens because the first one has a smaller slope, meaning that is larger at first, but as x grows the price does not grow as much as in Skate City

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Given that (8,-1) is on the graph of f(x), find
Nikolay [14]

Answer:

(-12, -1)

Step-by-step explanation:

(8, -1) => (-2/3x, f(-2/3x))

therefore

-2/3x = 8

x = 8 *-3/2

x = -12

f(-2/3x) = -1

therefore, the corresponding point is:

(-12,-1)

5 0
2 years ago
On January 1st Rosie Bank balances was $ 200. During the month, she wrote checks for 115.25 dollars, 315 dollars, and made one d
Firdavs [7]

Answer:

Step-by-step explanation:

$84.75

6 0
3 years ago
The sum of the first three terms in a GP is 38.Their product is 1728.Find the values of the three terms.
dusya [7]

Answer:

The value of the three terms is 8 and 18

Step-by-step explanation:

Let "a" be the first term and "r" be the common ratio.

Then from the condition, we have these two equations

   a + ar + ar^2  =   38,      (1)

   a*(ar*)*(ar^2) = 1728.      (2)

From equation (2),  a^3*r^3 = 1728,  or  (ar)^3 = 1728,   which implies

   ar = root%283%2C1728%29 = 12;          (3)    

hence,  

   r  = 12%2Fa.                   (4)

Now, in equation (1) replace the term  ar  by 12, based on (3).  You will get

   a + 12 + ar^2 =  38,   which implies

   a + ar^2 = 26.              (5)

Next, substitute  r = 12%2Fa  into equation (5), replacing "r" there.  You will get

   a + a%2A%28144%2Fa%5E2%29 = 26,   or

   a + 144%2Fa = 26.

Multiply by "a" both sides and simplify

   a^2 - 26a + 144 = 0,

   %28a-13%29%5E2 - 169 + 144 = 0

   %28a-13%29%5E2 = 25

   a - 13 = +/- sqrt%2825%29 = +/- 5.

Thus two solutions for "a" are  a = 13 + 5 = 18  or  a = 13 - 5 = 8.

If  a =  8, then from (4)  r = 12%2F8 = 3%2F2.

If  a = 18, then from (4)  r = 12%2F18 = 2%2F3.

   

In the first case, if a = 8,  then the three terms are  8, 8%2A%283%2F2%29 = 12  and  8%2A%283%2F2%29%5E2 = 18.

   In this case, the sum of terms is  8 + 12 + 18 = 38, so this solution does work.

In the second case, if a = 18,  then the three terms are  18, 18%2A%282%2F3%29 = 12  and  18%2A%282%2F3%29%5E2 = 8.

   In this case, the sum of terms is  18 + 12 + 8 = 38, so this solution does work, too.

ANSWER.  The problem has two solution:  

        a)  first term is 18;  the common difference is 2%2F3  and the progression is  18, 12, 8.

        b)  first term is  8;  the common difference is 3%2F2  and the progression is   8, 12, 18.

4 0
3 years ago
How to graph f(x)=2x^2-2
MariettaO [177]

Answer:

ew423q4rw32432ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph -2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2ph f(x)=2x^2-2erw3r5432

Step-by-step explanation:

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