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luda_lava [24]
4 years ago
13

sophia says that you can solve the problem in the Example by multiplying both quantities in the ratio 60 : 36 by 1 . Is Sophia c

orrect? Explain.
Mathematics
1 answer:
guapka [62]4 years ago
4 0

Answer:

No multiplying both quantities in the ratio 60 : 36 by 1  would not give the answer .

But multiplying both quantities in the ratio 60 : 36 by 1/6  would solve it.

Step-by-step explanation:

Multiplying any number or ratio by 1 gives the same answer no matter what the expression or how much bigger the number is.This will not give the solution .

If it is multiplied with a fraction like 1/6  that would give the correct answer.

Multiplying it with 1/6 reduces the ratio and gives a better estimate.

A:B

60:36

60*1/6: 36*1/6

10: 6

Meaning that for a total of 16 there are 10 of category A and 6 of category B.

But if we do the same procedure with the answer is same which does not solve the question.

A:B

60:36

60*1: 36*1

60: 36

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Find the mean, median, mode and range of 2,2,6,15,38,39
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Answer:

10.5

Step-by-step explanation:

2,2,6,15,38,39

6 and 15 are in the middle so add them

21 then divide by 2

10.5

6 0
3 years ago
Read 2 more answers
1. (8-2)+18×6= 2. (15+29-4)×4= 3. (13+5)×(13-5)= show steps please
NeX [460]

Use the order of operations (PEMDAS):

Parentheses, Exponents, Multiplication & Division, and then Addition & Subtraction

************************

1) (8 - 2) + 18 x 6

<u>Parentheses</u> (8 - 2)          

6 + 18 x 6    

<u>Multiplication</u> (18 x 6)

6 + 108

<u>Addition</u> (6 + 108)

114

**************************

2) (15 + 29 - 4) x 4

<u>Parentheses</u> (15 + 29 - 4)  

40 x 4

<u>Multiplication</u> (40 x 4)

160  

******************************

3) (13 + 5) x (13 - 5)

<u>Parentheses</u> (13 + 5) and (13 - 5)

18 x 8

<u>Multiplication</u> (18 x 8)

144

*********************************

Answers: 114, 160, 144


7 0
3 years ago
If 3x + 2y = 1 and<br> 2x + 7y = 3<br><br> How do you find x and y step by step?
trapecia [35]

Step-by-step explanation:

there are 2 main approaches (in their core they are the same, of course, but they look different) :

1. use one equation to express one variable by the second, and then use this in the second equation to solve for the remaining variable. with that you go back into the first equation and solve for the first variable.

2. multiply both equations by certain factors as needed, then add both results, so that there is one summary equation with only one variable, and then solve for it. then use that in one of the original equations and solve for the second variable.

using 1.

3x + 2y = 1

3x = 1 - 2y

x = (1 - 2y)/3

2x + 7y = 3

2(1 - 2y)/3 + 7y = 3

2(1 - 2y) + 21y = 9

2 - 4y + 21y = 9

17y = 7

y = 7/17

x = (1 - 2y)/3 = (1 - 2×7/17)/3 = (1 - 14/17)/3 =

= (17/17 - 14/17)/3 = 3/17 / 3 = 1/17

using 2.

multiply first equation by 2, the second by -3

6x + 4y = 2

-6x - 21y = -9

----------------------

0 -17y = -7

-17y = -7

17y = 7

y = 7/17

and so on (as under 1.).

6 0
2 years ago
Read 2 more answers
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Answer:

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8 0
3 years ago
The swim club rents the municipal pool for a flat fee of $500 plus a charge of $75 per swimmer during
xxTIMURxx [149]

Answer:

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