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Rus_ich [418]
4 years ago
10

The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle

Mathematics
1 answer:
Lina20 [59]4 years ago
4 0

The length of rectangle is 31 yards and width is 24 yards.

Step-by-step explanation:

Given,

Width of rectangle = w

Length of rectangle = w+7

Area of rectangle = 744 square yards

Area = Length * width

744=w(w+7)\\744=w^2+7w\\0=w^2+7w-744\\w^2+7w-744=0

Factorizing the equation

w^2+31w-24w-744=0\\w(w+31)-24(w+31)=0\\(w+31)(w-24)=0

Either,

w+31=0,    =>w= -31

Or,

w-24=0     =>w=24

As width cannot be negative, therefore,

Width = 24 yards

Length = w+7 = 24+7 = 31 yards

The length of rectangle is 31 yards and width is 24 yards.

Keywords: area, rectangle

Learn more about rectangles at:

  • brainly.com/question/2068148
  • brainly.com/question/2119883

#LearnwithBrainly

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Anuta_ua [19.1K]

QuestioN:

  • A container in the shape of of a frustum of a cone having diameters of its two circular faces as 35 cm and 30 cm and vertical height 14 cm, is completely filled with oil. if each of oil has mass 1.2 g, then find the cost of oil in the container if it costs $ 40 per kg.

{\large{\frak{\pmb{\underline{ Clearly,\:we\: have}}}}}

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:r = \bf\dfrac{30}{2}\:cm=15\:cm

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:R = \bf\dfrac{35}{2}\:cm=17.5\:cm

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:h = 14\:cm

\:\:\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━━

\:

{\bold { \underline{\small{Now,}}}}

\:\:\large{\ddagger}\underline {\footnotesize{\boxed{\frak{Volume_{(container)}={\frak{\orange{\bigg\{\bf\dfrac{1}{3}\pi (R^2+r^2+Rr)h\bigg\}cu}}}}}}}

\:\:

\:

\sf {\scriptsize\Bigg[\bf\dfrac{1}{3}\times \bf\dfrac{22}{7}\times\Bigg\{\bigg(\dfrac{35}{2}\bigg)^2+(15)^2+\dfrac{35}{2}\times 15\Bigg\}\times 14 \Bigg]cm^3}

\:\:

\:

\sf \:\:\:\:\:\rightarrowtail\: \dfrac{44}{3}\times\bigg(\dfrac{1225}{4}+225+\dfrac{525}{2}\bigg)cm^3

\:\:

\:

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\: \bigg( \dfrac{44}{3}\times \dfrac{3175}{4}\bigg)cm^3

\:\:

\:

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\: \bigg( \dfrac{3175 \times 11}{3}\bigg)cm^3

\:\:

\:

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\small{\underline{\mathcal{\red{Mass\:of\:1\:cm^3\:of\:oil\:=\:1.2\:g }}}}

\:\:

\:

\:\:\:\:\:\:\:\sf \footnotesize{Mass_{(oil\:in\:the\: container)}=\bigg( \dfrac{3175 \times 11}{3}\times1.2 \bigg)\:g}

\:\:

\:

\sf\:\:\:\:\:\:\:\:\rightarrowtail\:\bigg( \dfrac{3175 \times 11}{3}\times\dfrac{12}{10}\times\dfrac{1}{1000}\bigg)\:kg

\:\:

\:

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\:\dfrac{1397}{100}\:kg\:=13.97\:kg

\:\:

\:

  • \bf\twoheadrightarrowCost of oil at $40 per kg = $(13.97×40)\:\:=\:\large{\underline{\mathcal{\purple{\$\:558.80.}}}}
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