What was the approximate increase in diameter of chest circumference during a quiet inspiration?
1 answer:
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Answer:
(a) h^-1(x) = (x+6)/6
Step-by-step explanation:
The inverse relation can be found by solving for y: x = h(y).
<h3>Solution</h3>x = h(y) . . . . . the inverse relation
x = 6y -6 . . . . . use the function definition
x +6 = 6y . . . . add 6
(x +6)/6 = y . . . . divide by 6
The inverse function is ...