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alisha [4.7K]
2 years ago
11

An airplane begins a descent to a sea-level airport at an angle of -4° to the horizon. What is the change in elevation after it

flies 10,000 feet horizontally toward the runway if the original horizontal distance was 15000 feet ?
Mathematics
1 answer:
mote1985 [20]2 years ago
7 0

Using the slope concept, it is found that the change in elevation was of -699 feet.

<h3>What is a slope?</h3>

The slope is given by the <u>vertical change divided by the horizontal change</u>, and it's also the tangent of the angle of depression.

In this problem, we have that:

  • The vertical change is of h.
  • The horizontal change is of 10,000 feet.
  • The angle is of -4º.

Hence:

tan(-4º) = h/10000

h = 10000 x tan(-4º)

h = -699.

More can be learned about the slope concept at brainly.com/question/18090623

#SPJ1

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Step-by-step explanation:

We have:

The unit fraction = \dfrac{1}{2}

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∴ The next four multiples of the unit fraction \dfrac{1}{2}

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