All categories

2 years ago

PLS HELP ILL GIVE YOU FREE PIONTS AND BRAINLEST PLSSS

Mathematics

2 answers:

Fantom [35]2 years ago

7 0

Answer:

BDCAE

Step-by-step explanation:

hope this help

Georgia [21]2 years ago

5 0

Answer:

B,D,C,A,E

Step-by-step explanation:

-1, -4/3, 1/2, 2, 2 1/4

You might be interested in

Find the slope between: (1,-2) (2,-2)

stiks02 [169]

Answer: the slope would be 0

Step-by-step explanation:

7 0

2 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{y} = \int\limits^a_b {\int\limits^a_b {x.\rho(x,y)} \, dA }$

$M_{x}$ and $M_{y}$ are moments of the lamina about x-axis and y-axis, respectively.

Calculating moments:

For moment about x-axis:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$

$M_{x} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2.y.(x+y)} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 {\int\limits^a_\frac{x}{2} {y.x+y^{2}} \, dy\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{y^{2}x}{2}+\frac{y^{3}}{3})}\, dx }$

$M_{x} = 2\int\limits^2_0 { ({\frac{x(-x+3)^{2}}{2}+\frac{(-x+3)^{3}}{3} -\frac{x^{3}}{8}-\frac{x^{3}}{24} )}\, dx }$

$M_{x} = 2.(\frac{-9.x^{2}}{4}+9x)$

$M_{x} = 2.(\frac{-9.2^{2}}{4}+9.2)$

$M_{x} = 18$

Now to find the x-coordinate:

x = $\frac{M_{y}}{m}$

x = $\frac{63}{4}$

x = 15.75

For moment about the y-axis:

$M_{y} = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2x.(x+y))} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {x^{2}+yx} \, dy\,dx }$

$M_{y} = 2.\int\limits^2_0 {y.x^{2}+x.{\frac{y^{2}}{2} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {x^{2}.(-x+3)+\frac{x.(-x+3)^{2}}{2} - {\frac{x^{3}}{2}-\frac{x^{3}}{8} } } \,dx }$

$M_{y} = 2.\int\limits^2_0 {\frac{-9x^3}{8}+\frac{9x}{2} } \,dx }$

$M_{y} = 2.({\frac{-9x^4}{32}+9x^{2})$

$M_{y} = 2.({\frac{-9.2^4}{32}+9.2^{2}-0)$

$M{y} =$ 63

To find y-coordinate:

y = $\frac{M_{x}}{m}$

y = $\frac{18}{4}$

y = 4.5

Center mass coordinates for the lamina are (15.75,4.5)

3 0

3 years ago

Find the measure of the arc or angle indicated

MariettaO [177]

Short Answer: arc LM = 110°
Comment
Any two angles that have their end points on the same end points as a chord and both moving away in the same direction (in this case down ) are equal. This is a fundamental fact about circles.

Equation
2x + 55 = x + 55
the only way this is going to make any sense is if x = 0. No other value is possible because it will destroy the equality.

Conclusion
Both angles = 55

But that's not what you are asked for.

What you are asked for
You want to know the measure of arc LM.
The angle connecting the center of the circle with its two arms running through the end points of the chord = the measure of arc LM

Draw a dot where the center of the circle is and call it O. Draw in <MOL
<MOL = 2* either of the 55° = 2 (<LKM) = 2 * 55 = 110° That's a property of the central angle.

The measure of arc LM = 110°

6 0

2 years ago

A card is drawn from the deck. What is the probability it is either black face card or a spade?

IRINA_888 [86]

Answer:

about 37% chance or, rounding to the nearest tenth, 36.5% chance

Step-by-step explanation:

since there are only 6 black face cards out of 52 cards, so the fraction is 6/52

there are also 13 spade cards out of 52 cards, so the fraction is 13/52

to find the percent you have to add the two fractions becuase all you want to do is draw a black face card or a spade card. when you add them you get 19/52

then dividing the fraction gives you .3653846154 on my calculator :)

4 0

3 years ago

11x+7y=49 in y=mx+b format

Korolek [52]

7y=49-11x
y=7-11x/7

y=-11x/7+7
I think?

4 0

3 years ago

Read 2 more answers