D. Since the dark part of the boomerang is on the different side, it had to have been rotated
After careful consideration i think I have an answer...
So if you notice, These two triangles are a reflection of each other.
Now even though these two triangles equal one another, we still have to consider the fact that they are different. (one side is the opposite of another)
So lets just name all the sides that equal each other.
∠N = ∠Q
NO = QS
QR = NP
PO = SR
∠S = ∠O
∠P = ∠R
(by the way i'm going to be saying {the reflective side} every time i want to refer to the side with the two lines :P) - so bare with me.
So therefore this would mean that ∠P = ∠S would be false, since one angle is from the side that is reflected and the other isn't. Makes sense?
So lets look over at the answers...
A.) PN = SQ
For this answer choice, PN is on the non reflective side, while SQ is on the reflective side. Soooo... This answer choice is wrong.
B.) NO = QR
NO is part of the unreflective side, while QR is part of the reflective side.
Therefore this answer is wrong. They must be part of the same side.
C.) ∠P = ∠S
∠P is on the unreflective side, while angle ∠S is on the reflective side.
There fore this answer is also wrong.
D.) ∠O = ∠S
Now ∠O is on the reflective side while ∠S is on the reflective as well.
There fore this answer is correct .
YOUR ANSWER IS.
D.) ∠O = ∠S
Good Luck! :)
Answer:
1.50x=18
x=12
Step-by-step explanation:
You have to divide 1.50 on both sides and 1.50x/1.50= x and 18/1.50=12 so x=12
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
