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blondinia [14]
3 years ago
6

Simplify the expression 53 + 3(5 − 3).

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

Answer:

Step-by-step explanation:

5-3=2

53+3(2)

53+6

=59

lubasha [3.4K]3 years ago
7 0

Answer:

5^9

Step-by-step explanation:

I got the question right

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P can be a range of numbers from 3 to 5.

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One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
Use the information given to answer the question. Vanessa and Moe record their quiz scores in music class for a semester. The do
Lorico [155]

Answer:

Vanessa records a total of <u>11</u> quiz scores

Moe records a total of <u>10</u> quiz scores

According to the data, Vanessa's mean score is 80

According to the data, Vanessa's median score is 85

The range of Moe's quiz score is 45

The interquartile range of Moe's quiz score is 16.25

Step-by-step explanation:

Vanessa's score is given in the dot plot

Moe's scores are; 75, 80, 90, 90, 95, 55, 100, 95, 85, 85

1) The number of quiz scores Vanessa records is given by the number of dots on the dot plot, n = 11 dots ≡ 11 quiz scores

2) The number of quiz scores Moe records is given by the number of data points, n = 10 data points ≡ 10 quiz scores

3) Vanessa's mean score = ∑x_i/n

∑x_i/n = (60 + 2× 65 + 75 + 4 × 85 + 2 × 90 +95)/11 = 80

Vanessa's mean score = 80

4) Vanessa's median score is the (11 + 1)/2 th score = Her 6th score = 85

Vanessa's median score = 85

5) The range of Moe's score = Her largest score - Her least score = 100 - 55 = 45

The range of Moe's score = 45

6) Sorting Moe's scores gives;

75, 80, 90, 90, 95, 55, 100, 95, 85, 85

55, 75, 80, 85, 85, 90, 90, 95, 95, 100

The first quartile, Q₁ = 11/4th score = 2.75th score = 75 + 0.75 × 5 = 78.75

The 3rd quartile, Q₃ = The 3/4×11 score = 8.25th score = 95 + 0.25 ×0 = 95

The interquartile range, I = Q₃ - Q₁ = 95 - 78.75 = 16.25

The interquartile range of Moe's quiz score = 16.25.

3 0
3 years ago
A cone and a cylinder have equal radius, r, and equal altitudes, h. If the slant height of the cone is l, then the ratio of the
77julia77 [94]

Given:

radius of cone = r

height of cone = h

radius of cylinder = r

height of cylinder = h

slant height of cone = l

Solution

The lateral area (A) of a cone can be found using the formula:

A\text{ = }\pi rl

where r is the radius and l is the slant height

The lateral area (A) of a cylinder can be found using the formula:

A\text{ = 2}\pi rh

The ratio of the lateral area of the cone to the lateral area of the cylinder is:

\pi rl\text{ : 2}\pi rh

Canceling out, we have:

\begin{gathered} =\frac{\pi rl}{2\pi rh} \\ =\text{ }\frac{l}{2h}\text{  or l:2h} \end{gathered}

Hence the Answer is option B

3 0
1 year ago
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