× + 20 + 2× = 10 - 2× - 15
1 answer:
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Answer:
The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Step-by-step explanation:
Given : The position of an object along a vertical line is given by , where s is measured in feet and t is measured in seconds.
To find : What is the maximum velocity of the object in the time interval [0, 4]?
Solution :
The velocity is rate of change of distance w.r.t time.
Distance in terms of t is given by,
Derivate w.r.t. time,
It is a quadratic function so its maximum is at vertex of the function.
The x point of the function is given by,
Where, a=-3, b=6 and c=7
As 1 lie between interval [0,4]
Substitute t=1 in the function,
Th maximum velocity is 10 ft/s.
Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.
Answer:
Step-by-step explanation:
To find this equation in standard form, first, write it in factored form. This looks like . Then, multiply the polynomials using the FOIL (First, Outside, Inside, Last) method.
- Following the FOIL method, you should multiply the first terms in each binomial,
, which equals
.
- Then, the outside terms,
. This equals
.
- Next, the inside terms,
.
- Finally, the last terms,
, this equals
.
Then, add all of the terms together . To get the standard form, combine like terms, this comes out to
.