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4 years ago

What is the two on 582.091 rounded to

2 answers:

7 0

It's just 582 because I cant round on to make it 3 582.091 rounds to 582.1 and u cant round on to make the 2 to a 3. 5 or above give it a shove 4 or below let it go

Agata [3.3K]4 years ago

5 0

Hope this helps!! 583.000

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Convert (10111)2 into decimal number system

Eva8 [605]

Answer:

$(10111)_2 = (23)_{10}$

Step-by-step explanation:

$(10111)_2 = (1 \times 2^4) + (0 \times 2 ^3) + (1 \times 2^2) + (1 \times 2) + (1 \times 2^0)$

$= 16 + 0 + 4 + 2 + 1\\=23$

4 0

3 years ago

What is the Linear Function?

MatroZZZ [7]

Answer: y = -0.2x + 1

Step-by-step explanation: Find the y intercept (b) and then find the slope (m) and use the equation y = mx + b.

7 0

3 years ago

A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove

Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

= 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.

6 0

3 years ago

ASAP! Simplify -5 - square root -44

Tju [1.3M]

Answer:

$\boldmath-5-2i\sqrt{\boldmath11}$

Step-by-step explanation:

The not simplified form is $-5-\sqrt{-44}$

you know that $\sqrt{a\times b} = \sqrt{a} \times\sqrt{b}$ is true a and b are both positive or one of it is negative (not both of them).

You can write -44 as -1 × 4 × 11 inside square root.

So, $\sqrt{-44} = \sqrt{-1\times4\times11}=\sqrt{-1}\times\sqrt{4}\times\sqrt{11}=i\times2\times\sqrt{11}$ ( $\sqrt{4}=2$ )

$\therefore -5-\sqrt{-44} = -5-2i\sqrt{11}$

(NOTE : You must know that $\boldmath\sqrt{\boldmath-1}$ is written as $\boldsymbol i$ )

5 0

4 years ago

The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of

Lunna [17]

Answer:

Change in area=24 $\pi$ -48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square= $s^{2}$

Area of circle= $\pi r^{2}$

Area enclosed= $(\pi r^{2})-s^{2}$

dA/dt=2 $\pi$ r(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2( $\pi$ )(6)(2)-2(24)(1)

Change in area=24 $\pi$ -48

6 0

3 years ago