Answer: The correct image is the one with 5 rows, and 9 hexagons in each row.
Explanation:
Just took the quiz
Answer:
Speed = 7.04434 m/s
Explanation:
Given that:
The radius of the circle = 6.5 m
The expression for the calculation of circumference is shown below as:

Thus,

Time taken = 5.8 seconds.
Thus, The speed is:

So,

<u>Speed = 7.04434 m/s</u>
The frictional force is too much compared to the gravitational force
Explanation:
This is because of the great amount of frictional force between the book and the wall.
Also, the force of gravity on the book is not high enough to cause motion of the book to slide downs.
Frictional force is a force that opposes motion.
- For the book to slide down, it must overcome the force of friction acting on it opposite to the direction of gravity.
- According to newton's first law 'a body will remain in its state of rest or uniform motion unless acted upon by an external force'.
- Assuming the external force is gravitational force, clearly we see that the force is less than the frictional exerted on the book by pinning it to the wall.
- This frictional force is a static friction that is on a body at rest, it must be overcome by a larger force before motion takes place.
Fr > fg
Fr is the frictional force
fg is the gravitational force
learn more:
Newton laws brainly.com/question/11411375
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Hi Pupil Here's Your Answer ::
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Pressure is defined as the force acting perpendicular on an unit area of the surface.
OR
The thrust per unit area is called Pressure.
let us see, on what factors the pressure depends?
Take a pin having a pointed end and a nail having blunt end. Press then against a cardboard by applying the same force. We find that the pin penetrates deep into the cardboard then the nail. In this case, force acting on two points of the cardboard is same but the area under the tip of the Pin is less than under the tip of the nail.
The effect of the forces of the scene magnitudes on the different area is different.
Conclusions : Pressure acting on the surface is inversely proportional to the area of the surface on which force acts.
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Hope this helps