1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klio [65]
2 years ago
12

A child is in danger of drowning in the Merimac river. The Merimac river has a current of 3.1 km/hr to the east. The child is 0.

6 km from the shore and 2.5 km upstream from the dock. A rescue boat with speed 24.8 km/hr (with respect to the water) sets off from the dock at the optimum angle to reach the child as fast as possible. How far from the dock does the boat reach the child?
Physics
1 answer:
kolezko [41]2 years ago
4 0
In a problem where a child is danger form drowning from a river who has a current of 3.1km/hr to east and the child is 0.6km fro the shore and the upstream is 2,5km from the dock. So base on the question the boat with a speed of 24.8 km/hr is 1.9 km because the child is 0.6 km off the dock so 2.5 minus 0.6
You might be interested in
A mixed cost contains Select one:
-Dominant- [34]

A mixed cost contains a variable element and a fixed element.

Option a

<u>Explanation:</u>

Mixed costs are those costs that has both variable and fixed component. Example: operating cost of a machinery includes fixed costs that cannot be changed with other variable costs like fuel, insurance, depreciation, etc.

It is also named as semi-variable costs. And the formula to calculate mixed cost is as follows,

y=a+b x

where,

  • y is the "total cost "
  • a is the "fixed cost per period"
  • b is the "variable rate per unit of activity"
  • x is the "number of units of activity"
3 0
2 years ago
What is the minimum force required to increase the energy of a car by 69 J over a distance of 42 m? Assume the force is constant
sineoko [7]
ANSWER: 1.6N (forth option)



EXPLANATION:
E= Force x displacement
69=F(42)
69/42 = F
F=1.64 N

Answer : 1.6N
3 0
2 years ago
Suppose you increase your walking speed from 7 m/s to 15 m/s in a period of 2 m. What is your acceleration?
likoan [24]

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed) = (15 m/s - 7 m/s) = 8 m/s

time for the change = 2 minutes = 120 seconds

Acceleration = (8 m/s) / (120 seconds)

Acceleration = 0.067 m/s²

7 0
3 years ago
An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
S_A_V [24]

Answer:

Given:

Thermal Kinetic Energy of an electron, KE_{t} = \frac{3}{2}k_{b}T

k_{b} = 1.38\times 10^{- 23} J/k = Boltzmann's constant

Temperature, T = 1800 K

Solution:

Now, to calculate the de-Broglie wavelength of the electron, \lambda_{e}:

\lambda_{e} = \frac{h}{p_{e}}

\lambda_{e} = \frac{h}{m_{e}{v_{e}}              (1)

where

h = Planck's constant = 6.626\times 10^{- 34}m^{2}kg/s

p_{e} = momentum of an electron

v_{e} = velocity of an electron

m_{e} = 9.1\times 10_{- 31} kg = mass of electon

Now,

Kinetic energy of an electron = thermal kinetic energy

\frac{1}{2}m_{e}v_{e}^{2} = \frac{3}{2}k_{b}T

}v_{e} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{e}}}

}v_{e} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{9.1\times 10_{- 31}}}

v_{e} = 2.86\times 10^{5} m/s                    (2)

Using eqn (2) in (1):

\lambda_{e} = \frac{6.626\times 10^{- 34}}{9.1\times 10_{- 31}\times 2.86\times 10^{5}} = 2.55 nm

Now, to calculate the de-Broglie wavelength of proton, \lambda_{e}:

\lambda_{p} = \frac{h}{p_{p}}

\lambda_{p} = \frac{h}{m_{p}{v_{p}}                             (3)

where

m_{p} = 1.6726\times 10_{- 27} kg = mass of proton

v_{p} = velocity of an proton

Now,

Kinetic energy of a proton = thermal kinetic energy

\frac{1}{2}m_{p}v_{p}^{2} = \frac{3}{2}k_{b}T

}v_{p} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{p}}}

}v_{p} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{1.6726\times 10_{- 27}}}

v_{p} = 6.674\times 10^{3} m/s                               (4)                    

Using eqn (4) in (3):

\lambda_{p} = \frac{6.626\times 10^{- 34}}{1.6726\times 10_{- 27}\times 6.674\times 10^{3}} = 5.94\times 10^{- 11} m = 0.0594 nm

7 0
3 years ago
1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice
Paha777 [63]

1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase

<h2>please mark me as brainliest. ......</h2>

<h2>my friend. ....please help me .....</h2>
3 0
3 years ago
Other questions:
  • Consider a small child sliding down two differently shaped slides that have the same coefficient of kinetic friction. How must t
    14·1 answer
  • How can motion be described?
    15·2 answers
  • Keaton is asked to solve the following physics problem:
    6·1 answer
  • Think about this hypothetical (not real) situation: Astronaut Dustin and Astronaut Barb are floating in space. The force of grav
    12·1 answer
  • If a typical smelt weighs 225 g, what is the total mass of pcbs in a smelt in the great lakes?
    5·1 answer
  • Is the topic of atoms and elements a branch of physics??
    13·1 answer
  • Which three forms of light are invisible light?
    9·2 answers
  • A car is traveling 50 mph. It leaves Boston, Massachusetts at 5 a.m. and is
    7·1 answer
  • A golfer is 40.8 meters away from the green and swings so that the ball has an initial velocity of +20 m/s. Which of the followi
    5·1 answer
  • a student attaches a 0.5 kg object to a 0.7 m string and rotates the object around her head and parallel to the ground. how much
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!