Answer:
We live in a very adaptable environment. If we cannot adapt to the environment, we will not be able to survive.
Explanation:
Answer:
Explanation:
We need only to apply the definition of acceleration, which is:
In our case the final velocity is 
, the initial velocity is 
since it departs from rest, the final time is 
and the initial time we are considering is 
So for our values we have:
Answer
given,
ω₁ = 0 rev/s
ω₂ = 6 rev/s
t = 11 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
11 α = 6 - 0
= 0.545 rev/s²
The angular displacement
θ₁= ωi t + (1/2) α t²
θ₁= 0 + (1/2) (0.545)(11)^2
θ₁= 33 rev
case 2
ω₁ = 6 rev/s
ω₂ = 0 rev/s
t = 14 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
14 α = 0 - 6
= - 0.428 rev/s²
The angular displacement
θ₂= ωi t + (1/2) α t²
θ₂= 6 x 14 + (1/2) (-0.428)(14)^2
θ₂= 42 rev
total revolution in 25 s is equal to
θ = θ₁ + θ₂
θ = 33 + 42
θ = 75 rev
Answer: to achieve a stable octet of electrons in their outer shell
Explanation:
- Sodium (Na) has an atomic number of 11, and an electronic configuration of 1s2, 2s2 2p6, 3s1.
- Chlorine (CI) Sodium (Na) has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5.
Hence, sodium donates its single valence electron to chlorine, thereby achieving a stable octet structure of 1s2, 2s2 2p6 while chlorine accept the single electron also forming a stable octet structure of 1s2, 2s2 2p6, 3s2 3p6. Therefore, the reaction yields NaCl, an ionic compound with ionic (electrovalent) bond.
Na + Cl --> NaCl
Thus, Sodium(Na) and Chlorine (CI) want to form a lonic Bond because both acheive a completely filled outermost shell (octet structure)
