In the first 10 -> 10 - 9 = 1 (contain a 3).
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n ->
10^n - 9^n (contain a 3).
<u>The answer is 3.439 numbers contain a 3 in the first 10.000</u>
Answer:
44.2 years
Step-by-step explanation:
If we assume the interest is compounded annually and the investment is a one-time deposit into the account, its value each year is multiplied by 1+6.25% = 1.0625. After n years, the value in the account will be ...
19000 = 1300·1.0625^n
Dividing by 1300 and taking logs, we have ...
log(19000/1300) = n·log(1.0625)
log(190/13)/log(1.0625) = n ≈ 44.24 . . . . years
It will take about 44.2 years for the account to reach $19,000.
I gallon of water per 1 inch of fish
lemon tetra is 2 inches long
so 1 lemon tetra for 2 gallons of water
20/2 = 10
they can have 10 of them
equation would be X = 20/2
Answer:
This is the answer, if you don't understand, you can ask
Step-by-step explanation:
Let’s call the sum of the set of five numbers S and the sixth number N. We know the mean of the set of five numbers is 3k, so we can write the equation S/5 = 3k or S = 15k. When we add the sixth number the mean increases by k, so we can write the equations (S + N)/6 = 4k or S + N = 24k. Using S = 15k, we find that N = 9k. The ratio of the sixth number to the sum of the set of five numbers is therefore N/S = 9k/15k = 3/5.
