Answer:749.642
Step-by-step explanation:
Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:

a) P(between 236 and 281 days)

b) a) P(last between 236 and 296)

c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least
data lies within k standard deviation of mean.
For k = 2

Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
Answer:
$16
Step-by-step explanation:
1/4x4=1
So 4x4 = 16
Answer:
5
Step-by-step explanation:
Answer:
The number is 492,875.
Step-by-step explanation:
Given:
A number that is = 
Place value of 4 = 
Place value is ten thousands.
We have to identify the number where the place value of 4 is 10 times of the given number.
Numbers given:
284,796 or 327,498 or 492,875 and 742,186.
Lets see the place value of 4 in each of the number.
⇒
-
place value of
is
. - Place value of 4 is thousands.
⇒
place value of
is
.- Place value of 4 is hundreds.
⇒
place value of
is
.- Place value of 4 is hundred thousands.
⇒
place value of
is
.- Place value of 4 is ten thousands.
Notes:
Ten thousands multiplied with ten is hundreds thousand.
⇒ 
So,
The number which has digit 4 as hundred thousands place values is 492,875.