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alexandr1967 [171]
3 years ago
13

Which of the following is(are) the solution(s( to |5x+2|=8?

Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0

Since, this is an absolute value expression. We know that there is going to be 2 solutions.

We know that either 5x + 2 = 8 and 5x + 2 = -8 are the solutions.

Steps to solve:

5x + 2 = 8

~Subtract 2 to both sides

5x + 2 - 2 = 8 - 2

~Simplify

5x = 6

~Divide 5 to both sides

5x/5 = 6/5

~Simplify

x = 6/5

Steps to solve:

5x + 2 = -8

~Subtract 2 to both sides

5x + 2 - 2 = -8 - 2

~Simplify

5x = -10

~Divide 5 to both sides

5x/5 = -10/5

~Simplify

x = -2

Best of Luck!

larisa [96]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that

|5x+2|=8

Note that

|x|=x for ×>0

|x|=-x for ×<0.

So, for the first case

|5x+2|=8

5x+2=8

5x=8-2

5x=6

x=6/5

Also, the second aspect.

|5x+2|=8

-(5x+2)=8

Divide both side by -

5x+2=-8

5x=-8-2

5x=-10

x=-10/2

x=-5

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densk [106]

<u>Question 8</u>

a^2 + 7a + 12

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When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).

An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.

a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)

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= -3 or -4

These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).

<u>Question 10</u>

-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18

Rewrite each fraction with a common denominator so you can combine the fractions into one.

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Answer:

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Answer:

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Step-by-step explanation:

The equation of the proportional is y = m x, where

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The rule of the slope of a line is m = \frac{y2-y1}{x2-x1} , where

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