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snow_tiger [21]
3 years ago
14

Which of the following indicates that the roots of a quadratic are irrational

Mathematics
1 answer:
yan [13]3 years ago
6 0
Answer would be D  You can have a rational discriminant for an irrational root, but you can also have rational discriminant for a rational root. So C is partially correct. 

<span>All prime discriminants will result in an irrational root, but not all irrational roots have prime discriminants </span>
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A spinner numbered 1 through 12 is spun. Find the probability that
anastassius [24]

Answer:

\dfrac{1}{6}

Step-by-step explanation:

Let <em>A</em> be the event of getting an odd number.

<em>P(A)</em> be the probability of getting an odd number.

Total odd numbers here are 6 i.e. \{1,3,5,7,9,11\}

Here, total numbers in the game are 12 i.e \{1,2,3,....,12\}.

Formula for probability of an <em>event E</em> can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A) = \dfrac{6}{12}\\\Rightarrow \dfrac{1}{2}

Let <em>B</em> be the event of getting 11.

<em>P(B)</em> be the probability of getting 11.

Total number of possible cases is 1.

P(B) = \dfrac{1}{12}

P(A \cap B) is the probability that we get 11 and an odd number.

Possible number of cases = 1

P(A\cap B) = \dfrac{1}{12}

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

P(B/A) = \dfrac{P(A \cap B)}{P(A)}\\\Rightarrow \dfrac{\dfrac{1}{12}}{\dfrac{1}{2}}\\\Rightarrow \dfrac{1}{6}

Hence, P(B/A) = \dfrac{1}{6}

4 0
3 years ago
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Solve the equation. -0.2(30) + 0.5x = 0.2(30 + x)
Travka [436]

Answer:

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Step-by-step explanation:

4 0
2 years ago
A fraction bar labeled 1. Under the 1 are 2 boxes containing one-half. Under the 2 boxes are 4 boxes containing one-fourth. 2 on
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Answer:

A fraction bar labeled 1. Under the 1 are 2 boxes containing one-half. Under the 2 boxes are 4 boxes containing one-fourth. 2 one-fourths are circled.

Step-by-step explanation:

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Alenkasestr [34]

Answer:

the equation is not correct....

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3 years ago
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AleksandrR [38]
Comparing map distance to real distance we get 2cm/4km. That means 1cm = 2km.

So the map distance is half the real distance (well, technically not as one is in cm and the other in km but it’s enough to think this way) and a real distance of 10km must mean a map distance of half that (again ignoring the units) so we get 5cm.
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