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4 years ago

Find the slope of (1,6) (-9,-20)

Mathematics

1 answer:

Arisa [49]4 years ago

8 0

To find the slope of two points you use the formula: $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

In this case we can assume that:

$y_{2}$ = -20

$y_{1} =6$

$x_{2} = - 9$

$x_{1} = 1$

Plug the above into the equation I gave you at the start and solve:

$\frac{-20 - 6}{-9 - 1}$

$\frac{-26}{-10}$

Now reduce:

$\frac{26}{10}$ ÷2

$\frac{13}{5}$

^^^Slope for these two points

Hope this helped!

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Evan has $70 in a savings account. The interest rate is 5% per year and is not

DedPeter [7]

Answer:

$73.5

Step-by-step explanation:

i=5%×$70×1

=$3.5

amount at end of 1 yr=$70+$3.5

=$73.5

4 0

3 years ago

Daniel bought a new pair of sunglasses for $41.75. The sales tax is 8%. What is the price of thesunglasses after tax is included

uysha [10]

Answer:

it's 45.09

Step-by-step explanation:

8% of 41.75 is 3.34

3.34 + 41.75 is 45.09

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3 years ago

What is the answer of (x + y + 2) (y+1)?

adelina 88 [10]

You have to combine like terms. The answer would be:

xy+y^2+x+3y+2

3 0

3 years ago

A) Findi

Romashka [77]

Answer:

Part A)

$\displaystyle \frac{dy}{dx}=-\frac{2xy+y^2}{x^2+2xy}$

Part B)

$\displaystyle y=-\frac{5}{8}x+\frac{9}{4}$

Step-by-step explanation:

We have the equation:

$\displaystyle x^2y+y^2x=6$

Part A)

We want to find the derivative of our function, dy/dx.

So, we will take the derivative of both sides with respect to x:

$\displaystyle \frac{d}{dx}\Big[x^2y+y^2x\Big]=\frac{d}{dx}\big[6\big]$

The derivative of a constant is 0. We can expand the left:

$\displaystyle \frac{d}{dx}\Big[x^2y\Big]+\frac{d}{dx}\Big[y^2x\Big]=0$

Differentiate using the product rule:

$\displaystyle \Big(\frac{d}{dx}\big[x^2\big]y+x^2\frac{d}{dx}\big[y\big]\Big)+\Big(\frac{d}{dx}\big[y^2\big]x+y^2\frac{d}{dx}\big[x\big]\Big)=0$

Implicitly differentiate:

$\displaystyle (2xy+x^2\frac{dy}{dx})+(2y\frac{dy}{dx}x+y^2)=0$

Rearrange:

$\displaystyle \Big(x^2\frac{dy}{dx}+2xy\frac{dy}{dx}\Big)+(2xy+y^2)=0$

Isolate the dy/dx:

$\displaystyle \frac{dy}{dx}(x^2+2xy)=-(2xy+y^2)$

Hence, our derivative is:

$\displaystyle \frac{dy}{dx}=-\frac{2xy+y^2}{x^2+2xy}$

Part B)

We want to find the equation of the tangent line at (2, 1).

So, let's find the slope of the tangent line using the derivative. Substitute:

$\displaystyle \frac{dy}{dx}_{(2,1)}=-\frac{2(2)(1)+(1)^2}{(2)^2+2(2)(1)}$

Evaluate:

$\displaystyle \frac{dy}{dx}_{(2,1)}=-\frac{4+1}{4+4}=-\frac{5}{8}$

Then by the point-slope form:

$y-y_1=m(x-x_1)$

Yields:

$\displaystyle y-1=-\frac{5}{8}(x-2)$

Distribute:

$\displaystyle y-1=-\frac{5}{8}x+\frac{5}{4}$

Hence, our equation is:

$\displaystyle y=-\frac{5}{8}x+\frac{9}{4}$

5 0

2 years ago

Can someone help me im looking for the the x

lara31 [8.8K]

Answer:

x = 4√5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

a is one leg
b is another leg
c is hypotenuse

Step-by-step explanation:

Step 1: Identify Variables

a = 19

b = x

c = 21

Step 2: Solve for x

Substitute [PT]: 19² + x² = 21²
Isolate x term: x² = 21² - 19²
Exponents: x² = 441 - 361
Subtract: x² = 80
Isolate x: x = √80
Simplify: x = 4√5

8 0

3 years ago