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lawyer [7]
3 years ago
10

Ana’s dachshund weighed 5 5/8 pounds when it was born . By age 4 the dog weighed 6 times as much. Fill each box with a number or

symbols from the list to show how to find the weight of Ana’s dog at age 4 . Not all numbers and symbols my be used
Mathematics
1 answer:
jeka57 [31]3 years ago
3 0

Answer: 33\frac{3}{4}\ pounds

Step-by-step explanation:

The weight of Ana's dog at the time of its birth= 5\frac{5}{8}\ pounds=\frac{45}{8}\ pounds

By age 4, the dog weighed 6 times as much.

Now, the weight of Ana’s dog at age 4 =6\times\frac{45}{8}=\frac{45\times3}{4}=\frac{135}{4}\ pounds

Since, \frac{135}{4}=33\frac{3}{4}

The weight of Ana’s dog at age 4 = 33\frac{3}{4}\ pounds

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Larry says 5×900 is less than 5×9000 is greater than 9000​
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A group of friends was working on a student film. They spent $330 on costumes, which was 55% of their total budget. What was the
wariber [46]

Answer:

$600

Step-by-step explanation:

Let "x" represent their total budget for the film.

Amount spent on costumes = $330

Percent spent on costumes = 55%

Therefore:

55% of x = $330

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Cross multiply

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55x = 33,000

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x = 33,000/55

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2 years ago
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Step-by-step explanation:

3 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if:a) a
lara31 [8.8K]

Answer:

A) 0.0009765625

B) 0.0060466176

C) 2.7756 x 10^(-17)

Step-by-step explanation:

A) This problem follows a binomial distribution. The number of successes among a fixed number of trials is; n = 10

If a 0 bit and 1 bit are equally likely, then the probability to select in 1 bit is; p = 1/2 = 0.5

Now the definition of binomial probability is given by;

P(K = x) = C(n, k)•p^(k)•(1 - p)^(n - k)

Now, we want the definition of this probability at k = 10.

Thus;

P(x = 10) = C(10,10)•0.5^(10)•(1 - 0.5)^(10 - 10)

P(x = 10) = 0.0009765625

B) here we are given that p = 0.6 while n remains 10 and k = 10

Thus;

P(x = 10) = C(10,10)•0.6^(10)•(1 - 0.6)^(10 - 10)

P(x=10) = 0.0060466176

C) we are given that;

P((x_i) = 1) = 1/(2^(i))

Where i = 1,2,3.....,n

Now, the probability for the different bits is independent, so we can use multiplication rule for independent events which gives;

P(x = 10) = P((x_1) = 1)•P((x_2) = 1)•P((x_3) = 1)••P((x_4) = 1)•P((x_5) = 1)•P((x_6) = 1)•P((x_7) = 1)•P((x_8) = 1)•P((x_9) = 1)•P((x_10) = 1)

This gives;

P(x = 10) = [1/(2^(1))]•[1/(2^(2))]•[1/(2^(3))]•[1/(2^(4))]....•[1/(2^(10))]

This gives;

P(x = 10) = [1/(2^(55))]

P(x = 10) = 2.7756 x 10^(-17)

3 0
3 years ago
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