25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
D=5/2. 5 over 2
Step-by-step explanation:
Cross multiply and solve for D
Answer:
x = 1 is not a solution to the equation
Step-by-step explanation:
2x + 4 = -3x - 2 x = 1
2(1) + 4 = -3(1) - 2
2 + 4 = -3 - 2
6 = -5 FALSE
Im pretty sure it would be product
Sum = <span>ax + by + c + 2ax - 3by + c + by - c
Adding and cancelling the like terms
Sum = 3 </span><span>ax - by + c
</span><span>a. 3ax - by + c</span>
