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Kazeer [188]
4 years ago
8

Ozone is made of oxygen. What is the formula of ozone if 36g occupies 16.8L at STP?

Chemistry
1 answer:
Scilla [17]4 years ago
6 0
The formula of ozone is O3.
Hope this helps~
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The ΔHfus for ethanol is 4.60 kJ/mol. If it takes 7500.0 Joules of energy to melt a sample of ethanol, how many grams of ethanol
timama [110]

Answer:

Explanation:

4 0
3 years ago
OP
Yuri [45]

the answer is d hope this helps

8 0
3 years ago
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If the rate of decrease for the partial pressure of N2H4N2H4 in a closed reaction vessel is 70 torr/htorr/h , what is the rate o
german

Answer:

r_{NH_3}=140torr/h

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

N_2H_4 (g) + H_2 (g) \rightarrow 2 NH_3

Thus, in terms of pressures, the rate becomes:

-r_{N_2H_4}=\frac{1}{2} r_{NH_3}

Thus, the rate of change for the partial pressure of ammonia turns out:

r_{NH_3}=2*(-r_{N_2H_4})\\r_{NH_3}=2*[-(-70torr/h)]\\r_{NH_3}=140torr/h

The rate of decrease of partial pressure of urea is taken negative as it is a reactant whereas ammonia a product which has 2 as its stoichiometric coefficient.

Best regards.

7 0
3 years ago
Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15

Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63

Your answer will be about 63%. 

Hope this helped you out! :-)
5 0
3 years ago
1.40 m3 is how many mL
Zarrin [17]

\LARGE{ \boxed{ \rm{ \pink{Solution:}}}}

We know, 1 m³ of space can hold 1000 l of the substance.

⇛ 1 m³ = 1000 l----(1)

And, 1 l is 1000 times more than 1 ml

⇛ 1 l = 1000 ml------(2)

So, From (1) and (2),

⇛ 1 m³ = 1000 × 1000 ml

⇛ 1m³ = 1000000 ml

We had to find,

⇛ 1.40 m³ = 1.40 × 1000000 ml

⇛ 1.40 m³ = 140/100 × 1000000 ml

⇛ 1.40 m³ = 1400000 ml

⇛ 1.40 m³ = 14,00,000 ml / 14 × 10⁵ ml / 1.4 × 10⁶ ml

☃️ <u>So</u><u>,</u><u> </u><u>1.40</u><u> </u><u>m</u><u>³</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>×</u><u> </u><u>1</u><u>0</u><u>⁵</u><u> </u><u>m</u><u>l</u><u> </u><u>/</u><u> </u><u>1.4</u><u> </u><u>×</u><u> </u><u>10</u><u>⁶</u><u> </u><u>ml</u><u>.</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
3 years ago
Read 2 more answers
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