This problem is providing us with the chemical equation depicting the production of ammonia from nitrogen and hydrogen at equilibrium and asks for the correct change when the concentration of nitrogen is increased. At the end, the answer is the forward reaction would increase to start reducing the concentration of N2.
<h3>Chemical equilibrium</h3>
In chemistry, chemical reactions not always reach a 100-% conversion when reactants get in contact in order to carry out the chemical reaction. Thus, there is a point wherein the concentrations remain the same and is called equilibrium.
In such a way, for this problem, we have the following chemical reaction at equilibrium:

Now, according to the Le Ch.atelier's principle, an increase in the concentration of any species, shifts the equilibrium away from it, which means that if we increase the concentration of nitrogen, a reactant, the forward reaction will be favored.
Thereby, the correct answer is "the forward reaction would increase to start reducing the concentration of N2".
Learn more about chemical equilibrium: brainly.com/question/26453983
A binary compound is a compound formed from two different elements. There may or may not be more than one of each element. A diatomic compound (or diatomic molecule) contains two atoms, which may or may not be the same.
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Nomenclature of Ionic and Covalent Compounds.
Answer:
This is the conversion factor, we have to use:
44 g / 1mol
Explanation:
The reaction for the methane combustion is:
CH₄ + 2O₂ → CO₂ + 2H₂O
First of all we use this conversion factor to determine the moles of methane, we used.
50.6 g . 1 mol / 16 g = 3.16 mol
So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂
To calculate the grams of produced dioxide:
3.16 mol . 44 g / 1mol = 139.04 g