Answer:
The solution for the system of linear equations 3x-y=10 and 2x+y=5 is x=3 y= -1
<u>Solution:
</u>
Given that two linear equations are 3x-y = 10 and 2x + y = 5
We have to find the values of “x” and “y”
Let us consider 3x – y =10 ---- eqn 1
2x + y = 5 --- eqn 2
From eqn 1 , rearranging the terms we get
y = 3x-10 --- eqn 3
By substituting the value of “y” from eqn 3 into eqn 2 we get,
2x + 3x – 10 = 5
On solving above expression, 5x – 10 = 5
5x = 15
x = 3
Substitute the value of “x” in eqn 1 to obtain “y” value
3(3) – y = 10
9 – y = 10
y = 9-10 = -1
Hence the solution for the system of linear equations 3x-y=10
and 2x+y=5 is x=3 and y= -1
Answer: 4 weeks and 5 days
Step-by-step explanation:
9 weeks = 63 days
63 + 2 = 65
4 weeks = 28 days
28 + 4 = 32
65 - 32 = 33
7 * 4 = 28
33 - 28 = 5
28 days = 4 weeks
The answer is y-x because there are y seats and x people leave and the key word is leave. When there is words like leave or less those give you hints that mean you are subtracting.
