Answer:
k=2
Step-by-step explanation:
We have got a right triangle LNO with sides = m,4 and 8
By Pythagorean theorem
m^2=4^2 +8^2
Or m^2 = 80 ... i
IN triangle NOM, 4^2 +k^2 = l^2
i.e. 16+k^2 = l^2... i
In triangle LNM, m^2+l^2 = (8+k)^2
Substitute for m^2 as 80,
i.e. 80+l^2 = 64+k^2 +16k ... iii
From i, l^2 = 16+k^2
Substitute in iii
80+16+k^2 = 64+k^2 +16k
16k = 32 or k =2
Answer: 4
Step-by-step explanation:
Let's make a table.
So we know that for 24 minutes, Heather can ring up 36 customers. Now, to get 6 customers, you need to divide 36 by 6.
So
36 = 24
/ 6 /6
_______
6 = <u>4</u>
D 288 1/3 = 96/288 3/4 = 216/288 5/32 = 45/288 8/9 = 256/288
1/3 times 96 3/4 times 72 5/32 times 9 8/9 times 32
Hope This Helped! :3
Answer:
Step-by-step explanation:
Given
Required
Use the expression to prove a trigonometry identity
The given expression is not complete until it is written as:
Going by the Pythagoras theorem, we can assume the following.
- a = Opposite
- b = Adjacent
- r = Hypothenuse
So, we have:
Having said that:
The expression can be further simplified as:
Substitute values for sin and cos
becomes
Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
