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igomit [66]
4 years ago
7

Total number of laptops he owns

Mathematics
1 answer:
antoniya [11.8K]4 years ago
8 0
He has 6 laptops I hope this was helpful
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Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
If on the unit circle C, the distance from P(1, 0) to the point T ( 4/5 , 3/5 ) is x, determine the coordinates of the point at
AveGali [126]

Answer:

(\frac{4}{5}, -\frac{3}{5}  )

Step-by-step explanation:

The point P(1,0) and T(\frac{4}{5}, \frac{3}{5}  ) are on the unit circle C and the arc length from P to T is x.

Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.

Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be \frac{4}{5} and the y-coordinate will be -\frac{3}{5}.

So, coordinates of T' are (\frac{4}{5}, -\frac{3}{5}  ).

Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)

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Which of the following is a binomial?
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\boxed{\ }+\boxed{\ } -\ a\ binominal, therefore\ your\ answer\ is:\\\\b.\ c^2-16
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A circle has a diameter of 10 millimeters. What is the area of the circle?
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Is it one of your test and none of the answers are gonna work
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What is the range of f(x)=4^x?
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