All categories

3 years ago

The answer to this question and how you got it

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

5 0

Answer:

the answer is D 125/144

Nadusha1986 [10]3 years ago

4 0

The answer is d. I cross multiplied. I did not simplify so it could most likely be c then

You might be interested in

I forgot to add the pic to my last question. Thank you.

docker41 [41]

V= 7x12×?
V=84x?
252÷84=3

4 0

4 years ago

Which binomial is a factor of the polynomial? x2 - 6x + 9

brilliants [131]

X^2 - 6x + 9 = ( x - 3 )^2

5 0

4 years ago

Read 2 more answers

Can someone please help me? Will give the brainlest!!

SCORPION-xisa [38]

Step-by-step explanation:

The ratio of the perimeters = the scale

P₂ / P₁ = 6 / 4 = 3 / 2

The ratio of the areas = the square of the scale

A₂ / A₁ = (6 / 4)² = (3 / 2)² = 9 / 4

Same for the triangles:

P₂ / P₁ = 6 / 3 = 2

A₂ / A₁ = (6 / 3)² = (2)² = 4

5 0

3 years ago

Please help solve this system of equations

stepan [7]

Make a substitution:

$\begin{cases}u=2x+y\\v=2x-y\end{cases}$

Then the system becomes

$\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}$

Simplifying the equations gives

$\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}$

which is to say,

$\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}$

$\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81$

$\implies\dfrac uv=\pm27$

$\implies u=\pm27v$

Substituting this into the new system gives

$\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1$

$\implies u=\pm27$

Then

$\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13$

(meaning two solutions are (7, 13) and (-7, -13))

8 0

3 years ago

Ethan goes to a store an buys an item that costs x dollars. He has a coupon for 5% off, and then a 9% tax is added to the discou

choli [55]

Well Ethan’s pretty cool

8 0

4 years ago