Standard form of the parabola function: (y-k) = a(x-h)²
vertex (h,k)==> vertex (2,-5) [given]. Now plug==> y+5 =a(x-2)²
To calculate a, plug in the equation the coordinates of A(3,4)
4+5 = a(3-2)² ==> 9=a
Finally the equation is f(x) = y+5 = 9(x-2) or y = 9(x-2)² -5
Or f(x) =y = 9x² - 36x + 3
Number one or 2? so i can help you
The answer would be 42
Because the 0.3 (from the number 41.3) and 0.7 make 1 so basically it would be 41+1=42
(Sorry if wrong! Mark brainiest if right!)
Answer:
To satisfy the hypotheses of the Mean Value Theorem a function must be continuous in the closed interval and differentiable in the open interval.
Step-by-step explanation:
As f(x)=2x3−3x+1 is a polynomial, it is continuous and has continuous derivatives of all orders for all real x, so it certainly satisfies the hypotheses of the theorem.
To find the value of c, calculate the derivative of f(x) and state the equality of the Mean Value Theorem:
dfdx=4x−3
f(b)−f(a)b−a=f'(c)
f(x)x=0=1
f(x)x=2=3
Hence:
3−12=4c−3
and c=1.
