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3 years ago

41.3+0.7 adding and subtracting decimals

2 answers:

8 0

The answer would be 42
Because the 0.3 (from the number 41.3) and 0.7 make 1 so basically it would be 41+1=42
(Sorry if wrong! Mark brainiest if right!)

hammer [34]3 years ago

5 0

Answer:

Step-by-step explanation:

Add 41.3 + 0.7

First, calculate the TENTH (not tens) place of both the decimals.

3+7=10

We shall bring over the 1 in the tens place of 10, as the maximum number you can write in a place is 9.

Now, add the whole numbers.

41+0+1=42

Since the whole number is 42, and the tenth place is filled with the number 0, the answer is simply 42.

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Simplify. 5√ 10 <br> 1) 2√ 2) 2√2 3) 10√2 4) 5√

Nataly_w [17]

For this case we have that the expression in its exact form is the same, that is:

$5 \sqrt {10}$

If it is expressed in decimal form we have:

$5 \sqrt {10} = 1.5849$

If we want equivalent expressions, we must first mention the following property of powers and roots:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

Then, we can rewrite the expression as:

$5 \sqrt {10} = \sqrt {5 ^ 2 * 10} = \sqrt {25 * 10} = \sqrt {250}$

Answer:

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3 years ago

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Harman [31]

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3 years ago

Read 2 more answers

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago

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Lady_Fox [76]

Answer:

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galben [10]

Answer:

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Step-by-step explanation:

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