Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)? 
Given the distance and time, the formula to obtain the speed is
 .
.
Applying this to our problem we have that 
 .
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that  . This formula implies that
. This formula implies that 
 . .
First, observer that  .
.
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, 
Then, applying 1) we have that 

So, Sam Whittingham’s time through the 200 m was 5.5549s.