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Sedaia [141]
3 years ago
12

Anyone know the answer? Also could you put down what equation I’m supposed to use?

Mathematics
1 answer:
goldenfox [79]3 years ago
5 0

Answer:

The bottom two are your answers.

Step-by-step explanation:

What you do is use the slope formula which is y_2-y_1/x_2-x_1.

So for PQ it will be 12(which is y_2)-6(which is y_1)/4(which is x_2)-5(which is x_1) which equals -6.

12-6/4-5=-6.

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Find BC :<br> I am having trouble finding can anyone help ?
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24 because 12 + 12 = 24 and and CD = DB

CB = CD + CB = 24 the triange ADC and ADB are equal
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3 years ago
Simply the expression below, assume the denominator does not equal zero
Hoochie [10]

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2x+1 / x +5

Step-by-step explanation:

8 0
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What is an expression equivalent to 11(5)+11(11)
inessss [21]

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3 0
3 years ago
Help please with this question!!!
Vesnalui [34]
1 - AB is the Hypotenuse, BC is the opposite, AC is the adjacent (next to)

AB is the Hypotenuse because it is across from the right angle. BC is the opposite because its on the opposite side of the angle. AC is next to (adjacent) of the angle.

2 - the ratio is 30/1 = 5/b

This is because S O/H C A/H T O/A or Sohcahtoa.

S is the sine, which is Opposite over Hypotenuse. C is the cosine, which is Adjacent over Hypotenuse, and T is tangent which is Opposite over Adjacent. So look at what we labeled, we need to find the adjacent side, or b, and we have the opposite side, 5. So what has opposite and adjacent? Tangent.

So we do tan(30)/1 = 5/b, and cross multiply.

Now the last question. Hypotenuse is always C. But the other two values don’t matter where you put them on the left side since its multiplication. So its 7.7^2 * 6^2 = c^2 which is 59.29 * 36 = C^2.
2134.44 = c^2. Square root sides so it is 46.2 = c. The answer is 46.2
7 0
3 years ago
if k is a constant, determine and state the value of kids such that the polynomial k^2x^3-6kx+9 divisible by x-1
ZanzabumX [31]
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k^2(1)^3-6k(1)+9=k^2-6k+9=(k-3)^2=0

which occurs for k=3.
5 0
3 years ago
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