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pishuonlain [190]
3 years ago
14

What is 90 decreased by 40%?

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0
Because it's decreasing, you use the formula (1-x/100)y with x the percentage decreased which is here 40, and y the number decreased which is here 90
So we get
(1-40/100) * 90
(100/100 - 40/100) * 90
60/100 * 90 
5400/100
54 
So 90 decreased by 40% is 54
Hope this Helps :)
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$950 is the selling price of the item only.

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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May it cost her $420 to drive 500 mi
djyliett [7]

Answer:

C(d) = \frac{1}{5}d + 320

Step-by-step explanation:

Given

d \to miles

C \to cost

So:

(d_1,C_1) = (500,420) --- May

(d_2,C_2) = (620,444) --- June

Required

Express as a function

Start by calculating the slope (m)

m = \frac{\triangle C}{\triangle d}

m = \frac{444-420}{620-500}

m = \frac{24}{120}

Simplify

m = \frac{1}{5}

The equation is:

C(d) = m(d - d_1) +C_1

C(d) = \frac{1}{5}(d - 500) +420

C(d) = \frac{1}{5}d - 100 +420

Take LCM

C(d) = \frac{1}{5}d + 320

6 0
3 years ago
Which Inequality is represented by the number line graph?
USPshnik [31]

Answer:

option C is your right answer

Step-by-step explanation:

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8 0
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Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

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vlada-n [284]
It can be any number so here is my awnser 437
5 0
3 years ago
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