Multiply (2x-5)(3x^2-4x+2)

Mathematics

1 answer:

fgiga [73]3 years ago

7 0

Answer:

$\large\boxed{(2x-5)(3x^2-4x+2)=6x^3-23x^2+24x-10}$

Step-by-step explanation:

$\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x-5)(3x^2-4x+2)\\\\=(2x)(3x^2)+(2x)(-4x)+(2x)(2)+(-5)(3x^2)+(-5)(-4x)+(-5)(2)\\\\=6x^3-8x^2+4x-15x^2+20x-10\\\\\text{combine like terms}\\\\=6x^3+(-8x^2-15x^2)+(4x+20x)-10\\\\=6x^3-23x^2+24x-10$

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