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3 years ago

What is the area of this circle? a 1,017.36 b 254.34 c 28.26 d 56.52

Mathematics

2 answers:

Licemer1 [7]3 years ago

5 0

Answer:

Step-by-step explanatiobn:

Rus_ich [418]3 years ago

4 0

Answer:

would say b

Step-by-step explanation:

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Pavlova-9 [17]

Answer:

3(2x+5)=3 6x+15 = 3 6x = -12 x =-2

9+9x=2x+2 9x-2x= 2-9 7x= -7 x=-1

Step-by-step explanation:

3 0

3 years ago

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For some JKL the side lengths are such that LJ< JK< KL what must be true about angles J, K, L

katovenus [111]

Answer:

it does not matter didjebejsusudhdhe

4 0

3 years ago

Select the correct answer.

IceJOKER [234]

Answer: Option D. y+2x=3

Solution

If a line with a slope of -2:

Slope: m=-2

crosses the y-axis at (0,3):

(0,3)=(0,b)→b=3

What is the equation of the line?

y=mx+b

Replacing the known values:

y=-2x+3

Adding 2x both sides of the equation:

y+2x=-2x+3+2x

y+2x=3

4 0

4 years ago

Please help with the question above :)!!! ^^

zhannawk [14.2K]

(-1,-9) because if we substituted 1 into x y would be 9 and if we substituted 1/2 into x y would be 3 but if we substituted -1 into x y would be 1/9 so therefore that value is incorrect

7 0

3 years ago

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

<u>Addition: </u>

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

<u>Multiplication: </u>

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

4 years ago