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Sergio039 [100]
4 years ago
14

How many Real Solutions

Mathematics
2 answers:
nexus9112 [7]4 years ago
5 0
Seems like 2 solutions to that equation. Not quite sure though, sorry.
Oduvanchick [21]4 years ago
5 0

Answer:

D.0

Step-by-step explanation:

Our system of equations is

  • y= x²+1
  • y=x

then we can conclude that

  • x²+1 = x
  • x²+1-x = 0
  • x²-x+1 = 0

This is a quadratic equation so we will use the dicriminant method:

Let Δ be our dicriminant

  • a= 1
  • b= -1
  • c= 1
  • Δ = (-1)²-4*1*1 = 1-4 = -3 < 0

The dicriminant is negative so this equation has no real solutions

the the system has no real solutions

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Step-by-step explanation:

Step 1: Simplify both sides of the equation.

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