Question

How many Real Solutions

Answer 1

Seems like 2 solutions to that equation. Not quite sure though, sorry.

Answer 2

Answer:

D.0

Step-by-step explanation:

Our system of equations is

• y= x²+1
• y=x

then we can conclude that

• x²+1 = x
• x²+1-x = 0
• x²-x+1 = 0

This is a quadratic equation so we will use the dicriminant method:

Let Δ be our dicriminant

• a= 1
• b= -1
• c= 1
• Δ = (-1)²-4*1*1 = 1-4 = -3 < 0

The dicriminant is negative so this equation has no real solutions

the the system has no real solutions