This problem involves the use of a kinematic equation since it involves the motion of an object. The equation for the height of the object is given as:
s = -<span>16*t^2+v_o*t
Also, the initial velocity, v_o, was also said to be equal to 128 ft/s.
For the first question, </span><span>the time(s) that the projectile will reach a height of 240 ft when v_o is 128 feet per second, can be solved using the given equation and the quadratic formula. The resulting quadratic equation is then </span>-16*t^2 + 128*t -240 =0, where a =16, b =128, and c =-240. The quadratic formula is equal to [-b <span>± sqrt(b^2 -4ac)]/2a. This gives two answers t = 3 seconds and t = 5 seconds. This might be because the projectile has a parabolic path, thus, it reaches the height of 240 ft, before and after it reaches a peak.
For the second question, the time it takes for the projectile to reach the ground is obtained by setting the distance, s, equal to zero. In this case, t = 8 seconds.</span>
Total is 1120
interest is 3.5
interest earn in 1 yr be p
so is p/ 100 × 3.5 ×4 = 1120
1120÷4= p/100x 3.5
280=p/100 x 3.5
280÷3.5= p/100
80=p/100
p= 8000
Answer:
175+13a-10b+2c
Step-by-step explanation:
Answer:
the 8 is in the hundredths place
Answer: x=42
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
- Solve for x.
- Add 10 and 4.
- Multiply the sum of 10 and 4 by 3. You must move it from the left member to the right member. Then, if 3 is dividing x, this will multiply the sum of 10 and 4. So, you have:
Therefore, you obtain that the value of x is 42
