Elijah will pass John after 5 hours, and they each will have traveled 310 miles. Then the correct option is C.
<h3>What is speed?</h3>
The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
We know that the speed formula
Speed = Distance/Time
John and Elijah are both driving from New York City to Richmond.
John leaves at 7:20 and averages 60 mph (miles per hour) on the way.
Elijah leaves at 7:30 and averages 62 mph on the way.
The situation is modeled by this system, where x is the number of hours after Elijah leaves and y is the distance each will travel.
y = 60x + 10 ...1
y = 62x ...2
The time is taken by Elijah to cross John will be
62x = 60x + 10
2x = 10
x = 5 hours
The distance traveled in 5 hours will be
y = 62 (5)
y = 310 miles
Elijah will pass John after 5 hours, and they each will have traveled 310 miles.
Then the correct option is C.
More about the speed link is given below.
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When you plot the numbers on a graph or draw a histogram using them, you find the distribution shapes are
Lake A: ∩
Lake B: ∪
Lake C: ∩
Lake D: ∩
Apparently the weights of fish in Lake B have a U-shaped distribution.
Answer:
where is the shape of your question
XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.
Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.
Condition to be determined that proves triangles to be congruent by HL.
<h3>What is HL of triangle?</h3>
HL implies the hypotenuse and leg pair of the right-angle triangle.
Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.
Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.
Learn more about HL here:
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In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
