Answer:
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Step-by-step explanation:
Let x number of $5, y number of $10 and z number of $20
The number of $5 bills exceeds twice the number of $10 bills by 4.
Therefore, x = 2y + 4
The number of $20 bills is 6 fewer than the number of $10 bills.
Therefore, z = y - 6
A wallet contains $460 in $5, $10, and $20 bills.
Therefore,
5x + 10y + 20z = 460
Substitute x and y into equation
5(2y+4) + 10y + 20(y-6) = 460
10y + 20 + 10y + 20y - 120 = 460
40y - 100 = 460
40y = 460 + 100
40y = 560
y = 14
- Put the value of y into x = 2y + 4 and solve for x
x = 2(14) + 4
x = 32
- Put the value of y into z = y - 6 and solve for z
z = 14 - 6
z = 8
Hence, the each type of bills,
Number of $5 bills = 32
Number of $10 bills = 14
Number of $20 bills = 8
Answers:
y = 50
angle AOB = 100
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Explanation:
Angle x is an inscribed angle that subtends or cuts off minor arc AB. This is the shortest distance from A to B along the circle's edge.
Angle y is also an inscribed angle that cuts off the same minor arc AB. Therefore, it is the same measure as angle x. We can drag point D anywhere you want, and angle y will still be an inscribed angle and still be the same measure as x.
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Point O is the center of the circle. This is because "circle O" is named by its center point.
Angle AOB is considered a central angle as its vertex point is the center of the circle.
Because AOB cuts off minor arc AB, and it's a central angle, it must be twice that of the inscribed angle that cuts off the same arc.
This is the inscribed angle theorem.
Using this theorem, we can say the following
central angle = 2*(inscribed angle)
angle AOB = 2*(angle x)
angle AOB = 2*50
angle AOB = 100 degrees
4x²+3x-10
= 4x² + 8x -5x - 10
= 4x (x+2) -5(x+2)
= (4x-5) (x+2)
Option C
First you want to put them in order from least to greatest.
65, 72, 74, 75, 86, 89, 93, 95, 96, 97, 100.
Now you count the numbers on the left and right until you get to the middle, there is an uneven number so therefor you wont have to do any extra math.
65, 72, 74, 75, 86, 89, 93, 95, 96, 97, 100. there is 5 on each side 89 being the median.
Now moving onto the mode. You will need all of them for this not taking out the ones of there being multiple.
95, 95, <span>96, 100, </span>86, 75, 75, 75, 74, 72, 89, 97, 93, 65
You need to find the number that there is the most of to find the mode. to do this keep score of how many of each of the numbers there is
95, 95, 96, 100, 86, 75, 75, 75, 74, 72, 89, 97, 93, 65 The most commonly occuring number is 75 in this dataset.
Reviewing our answers.
In the end the median is 89 and the mode is 75
