Answer:
a) 1st and 2nd
b) 4th one
Step-by-step explanation:
Xy=10
x+y=29
subtract x from both sides for second equation
y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=

so
x^2+29x+10=0
a=1
b=29
c=10
x=
x=
x=

x=

x=

or

those are the 2 numbers
aprox=-28.65 and -0.349
Answer:
h = 6
Step-by-step explanation:
Given he area of the banner expressed as;
A = ℎ(2ℎ−2)
h is the height of the banner
A is the area = 60
Substitute
60 = ℎ(2ℎ−2)
60 = 2h² - 2h
30 = h² - h
h²-h-30 = 0
Factorize;
h²-6h+5h-30 = 0
h(h-6)+5(h-6) = 0
(h-6)(h+5) = 0
h - 6 = 0 and h+5 = 0
h = 6 and -5
Since the height cannot be negative;
h = 6
Hence he height of the banner is 6
Answer:
(x, y) = (4, 9)
Step-by-step explanation:
You can use the second equation to write an expression for y.
y = 10 - 1/4x . . . . subtract 1/4x from the given 2nd equation
Now, substitute that for y in the first equation:
1/2x + 1/3(10 -1/4x) = 5
1/2x + 10/3 -1/12x = 5 . . . . eliminate parentheses
You can work this a couple of ways from here. One is to multiply by 12 to eliminate fractions. Another is to work with the numbers as they are. We'll do that, because we don't get enough practice doing arithmetic with fractions.
5/12x = 5/3 . . . . . subtract 10/3
x = (5/3)/(5/12) = 12/3 = 4
From above, we can use our expression for y:
y = 10 - 1/4·4 = 9
The solution is (x, y) = (4, 9).